   Chapter 13.4, Problem 13.4CYU

Chapter
Section
Textbook Problem

Assume you dissolve 10.0 g of sucrose (C12H22O11) in 225 mL (225 g) of water and warm the water to 60 °C. What is the vapor pressure of the water over this solution? (Appendix G lists P°(H2O) at various temperatures.)

Interpretation Introduction

Interpretation: The vapor pressure of water has to be identified.

Concept introduction:

Raoult’s law: The vapor pressure of the solvent over the solution Psolvent is proportional to the mole fraction of the solvent. The ideal solution obeys the Raoult’s law.

PsolventχsolventPsolvent,where,Psolventisthevapor pressure of the solvent over the solution,χsolventis mole fraction of solvent in solution, Psolvent is the vapor pressure of the pure solvent.

Explanation

Given data:

Mass of Sucrose = 10.0 g;Water =225 g Psolvent (vapor pressure of water at 60C ) =149.4 torr = 149.4 mmHg

Number of moles of water and number of moles of sucrose can be calculated using the equation:

No.ofmoles=massmolarmass

nsucrose=10.0g342.3g/mol=0.0292molnwater=225g18=12

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