   Chapter 13.4, Problem 26E

Chapter
Section
Textbook Problem

# A projectile is tired from a tank with initial speed 400 m/s. Find two angles of elevation that can be used to hit a target 3000 m away.

To determine

To find: The two angles of elevation that can be used to hit a target 3000 m away.

Explanation

Given:

v0=400ms and d=3000m .

Formula used:

Write the expression for horizontal distance (dorx) , when y=0 .

d=v02sin2αg (1)

Here,

v0 is the initial speed,

g is the gravity, which is 9.8ms2 , and

α is the angle of elevation.

Substitute 3000m for d , 9.8ms2 for g and 400ms for v0 in equation (1),

3000=(400)2sin2α9.83000(9.8)=(400)2sin2α29400=(160000)sin2αsin2α=29,400160,000

Rearrange the equation

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