   Chapter 13.CR, Problem 31E ### Algebra and Trigonometry (MindTap ...

4th Edition
James Stewart + 2 others
ISBN: 9781305071742

#### Solutions

Chapter
Section ### Algebra and Trigonometry (MindTap ...

4th Edition
James Stewart + 2 others
ISBN: 9781305071742
Textbook Problem

# Bacteria Culture A certain type of bacteria divides every 5   s . If three of these bacteria are put into a petri dish, how many bacteria are in the dish at the end of 1   min ?

To determine

The number of bacteria are in the dish at the end of 1min.

Explanation

Approach:

The nth term of the geometric sequence is given as,

an=arn1 ……(1)

Here, an is the nth term of the geometric sequence, n is the number of terms, a is the first term of the sequence and r is the common ratio of the sequence.

Given:

The bacteria divides in every 5s and three of these bacteria are put into a petri dish.

Calculation:

Since the bacteria divides in every 5s. So,

r=2

And, three of these bacteria are put into a petri dish at 0sec. So,

a=3

Since in 1min is equal to 60sec and in every 5sec the bacteria divides. So,

Calculate the number of times bacteria divides in 1min.

n=605=12

But the bacteria are put into a petri dish at 0sec then, the total number of terms will be,

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