   Chapter 14, Problem 14QAP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
12 views

# The molar heat of fusion of aluminum metal is 1 0. 79 Kj / mol , whereas its heat of vaporization is 293 . 4 Kj / mol . Why is the heat of fusion of aluminum so much smaller than the ham of vaporization? What quantity of heat would be required to vaporize 1 .00  g of aluminum at its normal boiling point? What quantity of ham would he evolved if 5 .00  g of liquid aluminum freezes at its normal freezing point? What quantity of heat would be required to melt 0. 1 0 5 mole of aluminum at its normal melting point?

Interpretation Introduction

(a)

Interpretation:

The reasons for the heat of fusion of aluminum so much smaller than the heat of vaporization should be determined.

Concept Introduction:

The heat of fusion refers to the amount of heat energy needed to melt 1mole of solid aluminum at its melting point.

The heat of vaporization refers to the amount of heat energy needed to convert 1mole liquid aluminum to vapor at its boiling point.

Explanation

The states of matter: solid, liquid and gas are formed due to differences in arrangement of molecules and the intermolecular forces. In a solid, molecules are closely packed with strong intermolecular forces acting between the molecules. In a liquid, the distance between the molecules increases and force of attraction decreases...

Interpretation Introduction

(b)

Interpretation:

The quantity of heat that would be required to vaporize 1g of aluminum at its normal boiling point should be calculated.

Concept Introduction:

The amount of heat energy needed to vaporize 1mol of aluminum at its boiling point is known as the heat of vaporization. The value of heat of vaporization of aluminum is 293.4 kJ/mol.

Interpretation Introduction

(c)

Interpretation:

The quantity of heat that would be evolved when 5 g of liquid aluminum would freeze at its normal freezing point should be calculated.

Concept Introduction:

The amount of heat energy that would be evolved to freeze 1mol of liquid aluminum at its normal freezing point is known as the heat of fusion. The value of heat of fusion of aluminum is 10.79 kJ/mol.

Interpretation Introduction

(d)

Interpretation:

The quantity of heat that would be required to melt 0.105 mole of aluminum at its normal melting point should be calculated.

Concept Introduction:

The amount of heat energy needed to melt 1 mole of aluminum at its normal melting point is known as the heat of fusion. The value of heat of fusion of aluminum is 10.79 kJ/mol.

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