   Chapter 14, Problem 17QAP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
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# The molar heats of fusion and vaporization for water are 6 .0 2 kJ / mol and 4 0. 6 kJ / mol respectively, and The specific heat capacity of liquid water is 4 . 18 J / g  ° C . What quantity of heat energy is required to melt 25 .0  g of ice at 0   ° C ? What quantity of heat is required for vaporize 37 . 5 g of liquid water at 1 00   ° C ? What quantity of heat is required to warm 55 . 2 g of liquid water from 0   ° C to 1 00   ° C ?

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Interpretation Introduction

Interpretation:

The heat required to melt 25g of ice at 00C, heat required to vaporize 37.5g liquid water at 1000C and heat required to warm 55.2g water from 00C to 1000C must be calculated.

Concept Introduction:

For melting and vaporization latent heat is used but for increasing temperature specific heat is used.

Explanation

Given information:

Molar heat of fusion and vaporization of water is 6.02kJ/mol and 40.6kJ/mol respectively.

The specific heat capacity of water is 4.18J/g0C.

Heat of fusion of ice is 6.02kJ/mol

So fusion of 18g ice needs 6.02kJ heat energy.

Fusion of 1g ice needs 6.02kJ18 heat energy.

Fusion of 25g ice needs (6.02×25)kJ18 heat energy =150.5kJ18 heat energy = 8.36kJ

Heat of vaporization of water is 40.6kJ/mol

So vaporization of 18g water needs 40.6kJ heat energy

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