Chapter 14, Problem 19PS

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

# Hydrogen peroxide, H2O2(aq), decomposes to H2O(ℓ) and O2(g) in a reaction that is first-order in H2O2 and has a rate constant k = 1.06 × 10−3 min−1 at a given temperature. (a) How long will it take for 15% of a sample of H2O2 to decompose? (b) How long will it take for 85% of the sample to decompose?

(a)

Interpretation Introduction

Interpretation:

The time taken for 15% of sample to decompose has to be given.

Concept introduction:

Rate law or rate equation: The relationship between the reactant concentrations and reaction rate is expressed by an equation.

aA + bBxXRate of reaction = k [A]m[B]n

Rate constant, k: It is a proportionality constant that relates rate and concentration at a given temperature.

Explanation

The time required for the reaction is calculated as,

â€‚Â Reactionâ€‰rateÂ =Â kÂ [H2O2].Given:TheÂ reactionÂ isÂ firstÂ orderÂ reaction,rateÂ lawÂ isÂ ,Â ln[H2O2]t=â€‰â€‰-ktâ€‰+â€‰ln[H2O2]0timeÂ =Â ?Therefore,ln[H2O2]t=â€‰â€‰-Â ktâ€‰+Â ln[H2O2]0lnÂ (85Â mol/L)Â Â Â Â Â =Â (1

(b)

Interpretation Introduction

Interpretation:

The time taken for 85% of sample to decompose has to be given.

Concept introduction:

Rate law or rate equation: The relationship between the reactant concentrations and reaction rate is expressed by an equation.

aA + bBxXRate of reaction = k [A]m[B]n

Rate constant, k: It is a proportionality constant that relates rate and concentration at a given temperature.

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