   # Compare the percent ionization of the base in Exercise 22a with the percent ionization of the base in Exercise 22d. Explain any differences. ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 14, Problem 24E
Textbook Problem
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## Compare the percent ionization of the base in Exercise 22a with the percent ionization of the base in Exercise 22d. Explain any differences.

Interpretation Introduction

Interpretation:

The percent ionization of the base in Exercise 22a is to be compared with the percent ionization of the base in Exercise 22d.

Concept introduction:

The ratio of the quantity of a given acid or a base, that has dissociated, to the initial concentration of the stated acid or base, multiplied by 100 , is termed as the percent dissociation of the acid or base.

To determine: A comparison between the percent ionization of the base in Exercise 22a with the percent ionization of the base in Exercise 22d.

### Explanation of Solution

To find the percent ionization of the first base

The percent ionization of a base is calculated by the formula,

α=KbC

Where,

• α is the degree of dissociation.
• Kb is the base ionization constant (equilibrium constant).
• C is the concentration.

Substitute the value of Kb and C in the above expression.

α=1.1×1080.1=3.316×104

Therefore, the percent ionization is 3.316×10-2%_ .

To find the percent ionization of the second base

Refer Exercise 22d.

The calculated value of [OH] is 1.3×105M .

The given initial concentration is 0.100M .

The percent ionization is calculated by the formula,

Percentionization=[OH]InitialConcentration×100

Substitute the value of [H+] and the value of initial concentration in the above expression

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