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Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692

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BuyFindarrow_forward

Chemistry In Focus

7th Edition
Tro + 1 other
Publisher: Cengage Learning,
ISBN: 9781337399692
Chapter 14, Problem 31E
Textbook Problem
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For each reaction, identify the oxidizing agent and the reducing agent:

a . C 2 H 2 +H 2 C 2 H 4 b . H 2 CO+H 2 O 2 H 2 CO 2 +H 2 O c . Fe 2 O 3 +3CO 2Fe+3CO 2

Interpretation Introduction

Interpretation:

The oxidizing and reducing agents for each of the given reactions are to be identified.

Concept Introduction:

Oxidation is the addition of an electronegative element or the removal of an electropositive element in a chemical reaction.

Reduction is the addition of an electropositive element or the removal of an electronegative element in a chemical reaction.

A chemical reaction in which both oxidation and reduction takes place simultaneously is called a redox reaction.

An oxidizing agent is a substance that oxidizes the other substance and gets reduced in a chemical reaction.

A reducing agent is a substance that reduces the other substance and gets oxidized in a chemical reaction.

Explanation of Solution

a) C2H2+H2C2H4.

The equation for the reaction of C2H2 with H2 is as follows:

C2H2+H2C2H4

An oxidizing agent gains electrons easily and a reducing agent loses electrons easily in a chemical reaction.

C21H2+1+H20C22H4+1

In this chemical reaction, the oxidation state of H2 is increased from 0 to +1 and the loss of electrons occurs from it. Therefore, H2 is the reducing agent.

In this chemical reaction, the oxidation state of C2H2 is reduced from 1 to 2 and the gain of electrons occurs to it. Therefore, C2H2 is the oxidizing agent.

b) H2CO+H2O2H2CO2+H2O.

The equation for the reaction of H2CO with H2O2 is as follows:

H2CO+H2O2H2CO2+H2O

An oxidizing agent gains electrons easily and a reducing agent loses electrons easily in a chemical reaction

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Chapter 14 Solutions

Chemistry In Focus
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