   Chapter 14, Problem 3T Mathematical Applications for the ...

11th Edition
Ronald J. Harshbarger + 1 other
ISBN: 9781305108042

Solutions

Chapter
Section Mathematical Applications for the ...

11th Edition
Ronald J. Harshbarger + 1 other
ISBN: 9781305108042
Textbook Problem

Let z = 6 x 2 + x 2 y + y 2 − 4 y +   9 . Find the pairs ( x , y ) that are critical points for z and then classify each as a relative maximum, a relative minimum, or a saddle point.

To determine

To calculate: The pairs (x,y) that are critical points for z and then classify each as a relative maxima, relative minima, and saddle points of z=6x2+x2y+y24y+9.

Explanation

Given Information:

The provided function is, z=6x2+x2y+y24y+9.

Formula used:

To calculate relative maxima and minima of the z=f(x,y),

1. Find the partial derivatives zx and zy.

2. Find the critical points, that is, the point(s) that satisfy zx=0 and zy=0.

3. Then find all the second partial derivatives and evaluate the value of D at each critical point, where D=(zxx)(zyy)(zxy)2=2zx22zy2(2zxy)2.

(a) If D>0, then relative minimum occurs if zxx>0 and relative maximum occurs if zxx<0.

(b) If D<0, then neither a relative maximum nor a relative minimum occurs.

For a function f(x,y), the partial derivative of f with respect to x is calculated by taking the derivative of f(x,y) with respect to x and keeping the other variable y constant and the partial derivative of f with respect to y is calculated by taking the derivative of f(x,y) with respect to y and keeping the other variable x constant. The partial derivative of f with respect to x is denoted by fx and with respect to y is denoted by fy.

For a function z(x,y), the second partial derivative,

1. When both derivatives are taken with respect to x is zxx=2zx2=x(zx).

2. When both derivatives are taken with respect to y is zyy=2zy2=y(zy).

3. When first derivative is taken with respect to x and second derivative is taken with respect to y is zxy=2zyx=y(zx).

4. When first derivative is taken with respect to y and second derivative is taken with respect to x is zyx=2zxy=x(zy).

Power of x rule for a real number n is such that, if f(x)=xn then f(x)=nxn1.

Chain rule for function f(x)=u(v(x)) is f(x)=u(v(x))v(x).

Constant function rule for a constant c is such that, if f(x)=c then f(x)=0.

Coefficient rule for a constant c is such that, if f(x)=cu(x), where u(x) is a differentiable function of x, then f(x)=cu(x).

Calculation:

Consider the function, z=6x2+x2y+y24y+9.

Recall that, for a function f(x,y), the partial derivative of f with respect to x is calculated by taking the derivative of f(x,y) with respect to x and keeping the other variable y constant and the partial derivative of f with respect to y is calculated by taking the derivative of f(x,y) with respect to y and keeping the other variable x constant.

Use the power of x rule for derivatives, the constant function rule, the chain rule, and the coefficient rule,

Thus,

zx=012x+2xy=02x(6+y)=0

Thus, x=0 or y=6.

And,

zy=0x2+2y4=0

Consider the equation, x=0

Substitute 0 for x in x2+2y4=0.

0+2y4=0y=2

Consider the equation, y=6

Substitute 6 for y in x2+2y4=0.

x2+2(6)4=0x2124=0x2=16x=±4

Thus, the critical points are (0,2), (4,6) and (4,6).

Recall that, for a function z(x,y), the second partial derivative, when both derivatives are taken with respect to x is zxx=2zx2=x(zx), when both derivatives are taken with respect to y is zyy=2zy2=y(zy), when first derivative is taken with respect to x and second derivative is taken with respect to y is zxy=2zyx=y(zx)

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

x2 2x 5 = 0

Applied Calculus for the Managerial, Life, and Social Sciences: A Brief Approach

In Exercises 516, evaluate the given quantity. log1,000

Finite Mathematics and Applied Calculus (MindTap Course List)

Change each percent to a decimal: 414

Elementary Technical Mathematics

Find the unit tangent vector for at t = –1.

Study Guide for Stewart's Multivariable Calculus, 8th

The area of the shaded region is given by:

Study Guide for Stewart's Single Variable Calculus: Early Transcendentals, 8th 