   Chapter 14, Problem 45P

Chapter
Section
Textbook Problem

A stretched string of length L is observed to vibrate in five equal segments when driven by a 630.-Hz oscillator. What oscillator frequency will set up a standing wave so that the string vibrates in three segments?

To determine
The oscillator frequency for a standing wave of the strings vibrates in three segments.

Explanation

Given Info: The length of the stretched string is L .

Formula for the frequency of nth harmonic is given by,

fn=(n2L)v

Here, fn is the nth harmonic frequency, n is the number of segments of waves, L is the length of the stretched string, and v is the velocity.

The fifth harmonic frequency of the wave is,

f5=(52L)v (1)

The third harmonic frequency of the wave is,

f3=(32L)v (2)

Rewrite the equation (1) and (2) by comparing the velocity.

f5(L2.5)=f3(L1.5)f52

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started 