Chemistry & Chemical Reactivity
9th Edition
ISBN: 9781133949640
Author: John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher: Cengage Learning
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Textbook Question
Chapter 14, Problem 48PS
The mechanism for the reaction of CH3OH and HBr is believed to involve two steps. The overall reaction is exothermic.
Step 1: Fast, endothermic
CH3OH + H+ ⇄ CH3OH2+
Step 2: Slow
CH3OH2+ + Br− → CH3Br + H2O
- (a) Write an equation for the overall reaction.
- (b) Draw a reaction coordinate diagram for this reaction.
- (c) Show that the rate law for this reaction is Rate = k[CH3OH][H+][Br−].
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Chapter 14 Solutions
Chemistry & Chemical Reactivity
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