   Chapter 14, Problem 54P

Chapter
Section
Textbook Problem

A pipe has a length of 0.750 m and is open at both ends. (a) Calculate the two lowest harmonics of the pipe. (b) Calculate the two lowest harmonics after one end of the pipe is closed.

(a)

To determine
The two lowest harmonics of the pipe.

Explanation

Given Info: The length of the pipe is 0.750m and speed of the sound in air is 343m/s .

Formula to calculate the harmonic frequencies of a pipe open at both ends is,

fn=nv2L

• fn is the harmonic frequencies of a pipe open,
• n is the harmonic number,
• v is the speed of the sound,
• L is the length of the pipe,

Substitute 1 for n, 0.750m for L, and 343m/s for v to find f1

f1=1(343m/s)2(0.750m)=228

(b)

To determine
The two lowest harmonics frequency after one end of the pipe is closed.

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