   Chapter 14, Problem 56P

Chapter
Section
Textbook Problem

The overall length of a piccolo is 32.0 cm. The resonating air column vibrates as in a pipe that is open at both ends. (a) Find the frequency of the lowest note a piccolo can play. (b) Opening holes in the side effectively shortens the length of the resonant column. If the highest note a piccolo can sound is 4.00 × 105 Hz, find the distance between adjacent antinodes for this mode of vibration.

(a)

To determine
The frequency of the lowest note that a piccolo can play.

Explanation

Given Info: The overall length of a piccolo is 32.0 cm and the resonating air column vibrates in a pipe is open at both ends.

Formula to calculate the lowest fundamental frequency at which the pipe is open at both ends is,

fn=nv2L (1)

• fn is the lowest fundamental frequency
• n is the harmonic number.
• v is the velocity of sound in air.
• L is the length of the piccolo.

Substitute 1 for n 343m/s for v , and 32.0 cm for L to find f1

(b)

To determine
The distance between the adjacent antinodes for piccolo’s mode of vibration.

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Calculate your protein RDA.

Understanding Nutrition (MindTap Course List)

Describe the physical and chemical properties of alkynes.

Chemistry for Today: General, Organic, and Biochemistry

Did Pangea or Gondwana form first?

Biology: The Unity and Diversity of Life (MindTap Course List) 