   # Consider the titration of 80.0 mL of 0.100 M Ba(OH) 2 by 0.400 M HCl. Calculate the pH of the resulting solution after the following volumes of HCl have been added. a. 0.0 mL b. 20.0 mL c. 30.0 mL d. 40.0 mL e. 80.0 mL ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 14, Problem 58E
Textbook Problem
63 views

## Consider the titration of 80.0 mL of 0.100 M Ba(OH)2 by 0.400 M HCl. Calculate the pH of the resulting solution after the following volumes of HCl have been added.a. 0.0 mLb. 20.0 mLc. 30.0 mLd. 40.0 mLe. 80.0 mL

(a)

Interpretation Introduction

Interpretation:

The concentration of HCl used in titration of a stated volume and concentration of Ba(OH)2 is given. The pH of the resulting solution after the addition of a given volume of HCl is to be calculated.

Concept introduction:

Titration is a process to determine the concentration of an unknown solution with the help of a solution of a known concentration value.

The pOH is calculated by the formula,

pOH=log10[OH]

The relation between pH and pOH is,

pH+pOH=14

### Explanation of Solution

Explanation

Given

Concentration of Ba(OH)2 is 0.100M .

The pOH is determined by the [OH] present in the solution.

In the given titration,

0.0mL of 0.4M HCl is added to the given 80mL of 0.100M Ba(OH)2 .

Since, Ba(OH)2 is a strong base, it completely dissociates into its ions. The major species present are OH,Ba2+ and H2O .

The complete dissociation of Ba(OH)2 leads to the formation of 2OH ions.

Therefore, the concentration of OH in 0.100M Ba(OH)2 is,

[OH]=2×0.100M=0.200M_

The concentration of OH is 0

(b)

Interpretation Introduction

Interpretation:

The concentration of HCl used in titration of a stated volume and concentration of Ba(OH)2 is given. The pH of the resulting solution after the addition of a given volume of HCl is to be calculated.

Concept introduction:

Titration is a process to determine the concentration of an unknown solution with the help of a solution of a known concentration value.

The pOH is calculated by the formula,

pOH=log10[OH]

The relation between pH and pOH is,

pH+pOH=14

(c)

Interpretation Introduction

Interpretation:

The concentration of HCl used in titration of a stated volume and concentration of Ba(OH)2 is given. The pH of the resulting solution after the addition of a given volume of HCl is to be calculated.

Concept introduction:

Titration is a process to determine the concentration of an unknown solution with the help of a solution of a known concentration value.

The pOH is calculated by the formula,

pOH=log10[OH]

The relation between pH and pOH is,

pH+pOH=14

(d)

Interpretation Introduction

Interpretation:

The concentration of HCl used in titration of a stated volume and concentration of Ba(OH)2 is given. The pH of the resulting solution after the addition of a given volume of HCl is to be calculated.

Concept introduction:

Titration is a process to determine the concentration of an unknown solution with the help of a solution of a known concentration value.

The pOH is calculated by the formula,

pOH=log10[OH]

The relation between pH and pOH is,

pH+pOH=14

(e)

Interpretation Introduction

Interpretation:

The concentration of HCl used in titration of a stated volume and concentration of Ba(OH)2 is given. The pH of the resulting solution after the addition of a given volume of HCl is to be calculated.

Concept introduction:

Titration is a process to determine the concentration of an unknown solution with the help of a solution of a known concentration value.

The pOH is calculated by the formula,

pOH=log10[OH]

The relation between pH and pOH is,

pH+pOH=14

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