If a ball is thrown straight up in the air with an initial velocity of 95ft/s, it's height in feet after t second is given by y = 95t - 16t2 . Find the average velocity for the time period beginning when t = 1 and lasting .01 seconds

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Q: Suppose a ball is dropped from a height of 4900 feet. Its position at time t is s(t) = –16t2 + 900.…

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Q: Suppose a ball is dropped from a height of 4900 feet. Its position at time t is s(t) = –16t2 + 900.…

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