   Chapter 14, Problem 61AP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
5 views

# Given the densities and conditions of ice, liquid water, and steam listed in Table 14.1, calculate the volume of 1 .0  g of water under each of these circumstances.

Interpretation Introduction

Interpretation:

The volume of 1.0 g of water under each of circumstances, ice, liquid water and steam should be calculated using the densities and conditions listed in Table 14.1.

Concept Introduction:

The density is defined as mass per unit volume or,

Density = Mass (g)Volume (cm3)Volume = MassDensity

Density of solid-state water at 0 0C,  1 atm = 0.9168 g/cm3

Density of liquid water at 0 0C,  1 atm = 0.9971 g/cm3

Density of steam at 0 0C,  1 atm = 5.88 × 104 g/cm3.

Explanation

From the density and mass, volume can be calculated as follows:

Volume of ice at 0 0C,  1 atm = MassDensity

= 1.0 g0.9168 g/cm3

= 1.1 cm3

Volume of liquid water at 0 0C,  1 atm = MassDensity

= 1.0 g0

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