   # Some properties of potassium metal are summarized in the following table: rmal melting point :math&gt; 63 . 5 ° C rmal boiling point :math&gt; 765 . 7 ° C lar heat of fusion :math&gt; 2 . 334 kJ / mol lar heat of vaporization :math&gt; 79 . 87 kJ / mol ecific heat of the solid :math&gt; 0. 75 J / g ° C Calculate the quantity of heat required to heat 5 .00 g of potassium from 25 . 3 ° C to 45 . 2 ° C . Calculate the quantity of heat required to melt 1 . 35 moles of potassium at its normal melting point. Calculate the quantity of heat required to vaporize 2 . 25 g of potassium at its normal boiling point. ### Introductory Chemistry: A Foundati...

8th Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781285199030

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

8th Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781285199030
Chapter 14, Problem 67AP
Textbook Problem
1 views

## Some properties of potassium metal are summarized in the following table:rmal melting point :math> 63 . 5  ° C rmal boiling point :math> 765 . 7  ° C lar heat of fusion :math> 2 . 334 kJ / mol lar heat of vaporization :math> 79 . 87 kJ / mol ecific heat of the solid :math> 0. 75 J / g  ° C Calculate the quantity of heat required to heat 5 .00  g of potassium from 25 . 3  ° C to 45 . 2  ° C . Calculate the quantity of heat required to melt 1 . 35 moles of potassium at its normal melting point. Calculate the quantity of heat required to vaporize 2 . 25 g of potassium at its normal boiling point.

Interpretation Introduction

(a)

Interpretation:

Quantity of heat required to heat 5.0g of potassium from 25.30C to 45.20C must be calculated.

Concept Introduction:

To increase the temperature of a solid we need to supply heat energy. Specific heat plays crucial role in increase of temperature of a substance.

### Explanation of Solution

The heat energy (H) required to increase temperature of a substance depends on mass of the substance (m), specific heat of the substance(s) and temperature rise (t). Thus we can write

H=m×s×t

Putting all the values we get

H=5g×0

Interpretation Introduction

(b)

Interpretation:

How much heat energy will be required to melt 1.35 mol of potassium at its normal melting point must be calculated?

Concept Introduction:

Melting point is the temperature at which a solid starts melting to liquid and until all the solid is not melted temperature remains same.

Interpretation Introduction

(c)

Interpretation:

How much heat energy will be required to vaporize 2.25g of potassium at its normal boiling point must be calculated?

Concept Introduction:

Boiling point is the temperature at which a liquid starts boiling to vapor and until all the liquid is not boiled off temperature remains same.

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