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Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097

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BuyFindarrow_forward

Chemistry

9th Edition
Steven S. Zumdahl
ISBN: 9781133611097
Textbook Problem

A solution is made by adding 50.0 mL of 0.200 M acetic acid (K4 = 1.8 × 10–3) to 50.0 mL of 1.00 × 10–3 M HCl

  a. Calculate the pH of the solution

  b. Calculate the acetate ion concentration.

(b)

Interpretation Introduction

Interpretation:

A solution is made by adding 50.0 mL of 0.200M Acetic acid to 50mL of 1×10-3M HCl .

  1. (a) pH of the solution is to be calculated.
  2. (b) Acetate ion concentration to be calculated.

Concept introduction:

The pH of a solution is define as a figure that expresses the acidity of the alkalinity of a given solution.

The pH of a solution is calculated by the formula, pH=log[H+]

The number of moles of a solute is calculated by the formula,

Molesofsolute=Volume(L)×Molarity

Explanation

To determine: Equilibrium concentration of Acetate ion

The moles of CH3COOH are 0.01mol_ and that of HCl are 5.0×10-5mol_ .

Given data

Volume of CH3COOH is 50.0mL(0.050L) .

Concentration of CH3COOH is 0.200M .

Volume of HCl is 50.0mL(0.050L) .

Concentration of HCl is 1.00×103M .

The number of moles of a solute is calculated by the formula,

Molesofsolute=Volume(L)×Molarity

Substitute the value of volume and molarity of CH3COOH and HCl in the above expression.

Calculation of moles of Acetic acid and Hydrochloric acid

For CH3COOH ,

MolesofCH3COOH=0.050L×0.200M=0.01mol_

For HCl ,

MolesofHCl=0.050L×(1.00×103)M=5.0×10-5mol_

Calculation of hydrogen ion forms HCl

The total volume of the solution is calculated by the formula,

Totalvolume=VolumeofCH3COOH+VolumeofHCl

Substitute the value of the volume of CH3COOH and the volume of HCl in the above expression.

Totalvolume=(0.050+0.050)L=0.1L

HCl is a strong acid. Therefore, it completely dissociates in water. Hence, the hydrogen ion concentration is equal to the concentration of HCl .

The concentration is calculated by the formula,

Concentration=NumberofmolesVolume(L)

Substitute the value of the number of moles of HCl and the volume in the above expression.

Concentration=5.0×105mol0.10L=5.0×10-4M_

Therefore, the [H+] from HCl is 5.0×10-4M_ .

Calculation of initial concentration of Acetic acid

The concentration is calculated by the formula,

Concentration=NumberofmolesVolume(L)

Substitute the value of the number of moles of CH3COOH and the volume in the above expression.

Concentration=0.01mol0.10L=0.1M_

Therefore, the initial [CH3COOH] is 0.1M_

(a)

Interpretation Introduction

Interpretation:

A solution is made by adding 50.0 mL of 0.200M Acetic acid to 50mL of 1×10-3M HCl .

  1. (a) pH of the solution is to be calculated.
  2. (b) Acetate ion concentration to be calculated.

Concept introduction:

The pH of a solution is define as a figure that expresses the acidity of the alkalinity of a given solution.

The pH of a solution is calculated by the formula, pH=log[H+]

The number of moles of a solute is calculated by the formula,

Molesofsolute=Volume(L)×Molarity

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Chapter 14 Solutions

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Ch-14 P-1ALQCh-14 P-2ALQCh-14 P-3ALQCh-14 P-4ALQCh-14 P-5ALQCh-14 P-6ALQCh-14 P-7ALQCh-14 P-8ALQCh-14 P-9ALQCh-14 P-10ALQCh-14 P-11ALQCh-14 P-12ALQCh-14 P-13ALQCh-14 P-14ALQCh-14 P-15ALQCh-14 P-16ALQCh-14 P-17ALQCh-14 P-18ALQCh-14 P-19QCh-14 P-20QCh-14 P-21QCh-14 P-22QCh-14 P-23QCh-14 P-24QCh-14 P-25QCh-14 P-26QCh-14 P-27QCh-14 P-28QCh-14 P-29QCh-14 P-30QCh-14 P-31QCh-14 P-32QCh-14 P-33QCh-14 P-34QCh-14 P-35ECh-14 P-36ECh-14 P-37ECh-14 P-38ECh-14 P-39ECh-14 P-40ECh-14 P-41ECh-14 P-42ECh-14 P-43ECh-14 P-44ECh-14 P-45ECh-14 P-46ECh-14 P-47ECh-14 P-48ECh-14 P-49ECh-14 P-50ECh-14 P-51ECh-14 P-52ECh-14 P-53ECh-14 P-54ECh-14 P-55ECh-14 P-56ECh-14 P-57ECh-14 P-58ECh-14 P-59ECh-14 P-60ECh-14 P-61ECh-14 P-62ECh-14 P-63ECh-14 P-64ECh-14 P-65ECh-14 P-67ECh-14 P-68ECh-14 P-69ECh-14 P-70ECh-14 P-72ECh-14 P-73ECh-14 P-74ECh-14 P-75ECh-14 P-76ECh-14 P-77ECh-14 P-78ECh-14 P-79ECh-14 P-80ECh-14 P-81ECh-14 P-82ECh-14 P-83ECh-14 P-84ECh-14 P-85ECh-14 P-86ECh-14 P-87ECh-14 P-88ECh-14 P-89ECh-14 P-90ECh-14 P-91ECh-14 P-92ECh-14 P-93ECh-14 P-94ECh-14 P-95ECh-14 P-96ECh-14 P-97ECh-14 P-99ECh-14 P-100ECh-14 P-101ECh-14 P-102ECh-14 P-103ECh-14 P-104ECh-14 P-105ECh-14 P-106ECh-14 P-107ECh-14 P-108ECh-14 P-109ECh-14 P-110ECh-14 P-111ECh-14 P-112ECh-14 P-113ECh-14 P-114ECh-14 P-115ECh-14 P-116ECh-14 P-117ECh-14 P-118ECh-14 P-119ECh-14 P-120ECh-14 P-121ECh-14 P-122ECh-14 P-123ECh-14 P-124ECh-14 P-125ECh-14 P-126ECh-14 P-127ECh-14 P-128ECh-14 P-129ECh-14 P-130ECh-14 P-131ECh-14 P-132ECh-14 P-133ECh-14 P-134ECh-14 P-135ECh-14 P-136ECh-14 P-137ECh-14 P-138ECh-14 P-139ECh-14 P-140ECh-14 P-141ECh-14 P-142ECh-14 P-143AECh-14 P-144AECh-14 P-145AECh-14 P-146AECh-14 P-147AECh-14 P-148AECh-14 P-149AECh-14 P-150AECh-14 P-151AECh-14 P-152AECh-14 P-153AECh-14 P-154AECh-14 P-155AECh-14 P-156AECh-14 P-157AECh-14 P-158AECh-14 P-159AECh-14 P-160AECh-14 P-161AECh-14 P-162CWPCh-14 P-163CWPCh-14 P-164CWPCh-14 P-165CWPCh-14 P-166CWPCh-14 P-167CWPCh-14 P-168CWPCh-14 P-169CWPCh-14 P-170CPCh-14 P-171CPCh-14 P-172CPCh-14 P-173CPCh-14 P-174CPCh-14 P-175CPCh-14 P-176CPCh-14 P-177CPCh-14 P-178CPCh-14 P-179CPCh-14 P-180CPCh-14 P-181CPCh-14 P-182CPCh-14 P-183CPCh-14 P-184CPCh-14 P-185CPCh-14 P-186CPCh-14 P-187IPCh-14 P-188IPCh-14 P-189IPCh-14 P-190MPCh-14 P-191MP

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