Chapter 14.1, Problem 14.1CYU

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

# Sucrose decomposes to fructose and glucose in acid solution. A plot of the concentration of sucrose as a function of time is given in the margin. What is the rate of change of the sucrose concentration over the first 2 hours? What is the rate of change over the last 2 hours?Concentration versus time for the decomposition of sucrose.

Interpretation Introduction

Interpretation:

The rate of change over the given time intervals has to be given.

Concept Introduction:

The rate of reaction is the quantity of formation of product or the quantity of reactant used per unit time.  The rate of reaction doesn’t depend on the sum of amount of reaction mixture used.

The raise in molar concentration of product of a reaction per unit time or decrease in molarity of reactant per unit time is called rate of reaction and is expressed in units of mol/(L.s) .

The equation that relates the reaction rate to the reactants concentrations that is raised to various powers is called as rate law.

Rate law can be determined by the slow step or otherwise called as rate-determining step.

Rate constant is defined as proportionality constant in the connection between rate and concentrations.

Explanation

The rate of the reaction is calculated as,

â€‚Â Rateâ€‰ofâ€‰decompositionâ€‰ofâ€‰dyeÂ  = Â -changeÂ inÂ [dye]changeÂ inÂ timeÂ  = Â -Î”[dye]Î”tAtâ€‰tÂ =Â 0,Â theÂ concentrationÂ ofÂ dyeÂ  = Â 0.05Â mol/LAtÂ tÂ =Â 2Â hrs,Â theÂ concentrationÂ ofÂ dye Â =Â  0.034Â mol/LChangeÂ inÂ concentration Â =Â cfinal-cinitial = (0.05â€‰mol/L)-(0.034â€‰mol/L)Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â  Â =Â 0.016Â mol/LRateâ€‰ofâ€‰decompositionâ€‰ofâ€‰dyeÂ Â  =Â  -Î”[dye]Î”t = -(0

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