Chapter 14.2, Problem 14.2P

a.

Interpretation Introduction

Interpretation:

Arabinose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Simplest carbohydrates are known as monosaccharides.  They contain three to six carbons generally in a chain form with a carbonyl group present in the terminal or the adjacent carbon atom from the terminal.  Monosaccharides that have the carbonyl group at the terminal carbon atom $\text{C1}$ are known as aldoses and the monosaccharides that have the carbonyl group on the adjacent carbon atom $\text{C2}$ are known as ketoses.

The number of carbon atoms present in the chain characterize the monosaccharide.  They are given below.

• Carbon chain with three carbon atoms is triose.
• Carbon chain with four carbon atoms is tetrose.
• Carbon chain with five carbon atoms is as pentose.
• Carbon chain with six carbon atoms is as hexose.

b.

Interpretation Introduction

Interpretation:

Threose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Refer part “a.”.

c.

Interpretation Introduction

Interpretation:

Erythrulose has to be classified based on the number of carbon atoms present in the chain and also the carbonyl group.

Concept Introduction:

Refer part “a.”.