Chapter 14.3, Problem 14.4CYU

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

# The rate constant, k, at 25 °C is 0.27/h for the reactionPt(NH3)2Cl2(aq) + H2O(ℓ) → [Pt(NH3)2(H2O)Cl]+(aq) + Cl‒(aq)and the rate equation isReaction rate = k[Pt(NH3)2C12]Calculate the rate of reaction when the concentration of Pt(NH3)2Cl2 is 0.020 M.

Interpretation Introduction

Interpretation: The rate of the reaction has to be given.

Concept Introduction:

Rate law or rate equation: The relationship between the reactant concentrations and reaction rate is expressed by an equation.

aA + bBxXRate of reaction = k [A]m[B]n

Order of a reaction: The order of a reaction with respect to a particular reactant is the exponent of its concentration term in the rate law expression, and the overall reaction order is the sum of the exponents on all concentration terms.

Rate constant, k: It is a proportionality constant that relates rate and concentration at a given temperature.

Explanation

The reaction rate of the chemical reaction is given as,

â€‚Â Reactionâ€‰rateÂ =Â kÂ [Pt(NH3)2Cl2].Given:[Pt(NH3)2Cl2]Â =Â 0.020Â MkÂ =Â 0.27Â h-1Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Reactionâ€‰rateÂ =Â ?Therefore,Reaction

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