   # The reaction NO(g) + 1/2 Cl 2 (g) → NOCl(g) is first-order in [Cl 2 ] and second-order with respect to [NO]. Under a given set of conditions, the initial rate of this reaction is 620 × 10 −6 mol/L ∙ s. What is the rate of this reaction if the concentration of NO is doubled and the concentration of Cl 2 is reduced to half the original value? (a) 6.20 ×10 −6 mol/L ∙ s (b) 124 × 10 −5 mol/L ∙ s (c) 2.48 × 10 −5 mol/L ∙ s (d) 4.96 × 10 −5 mol/L ∙ s ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 14.3, Problem 1RC
Textbook Problem
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## The reaction NO(g) + 1/2 Cl2(g) → NOCl(g) is first-order in [Cl2] and second-order with respect to [NO]. Under a given set of conditions, the initial rate of this reaction is 620 × 10−6 mol/L ∙ s. What is the rate of this reaction if the concentration of NO is doubled and the concentration of Cl2 is reduced to half the original value? (a) 6.20 ×10−6 mol/L ∙ s (b) 124 × 10−5 mol/L ∙ s (c) 2.48 × 10−5 mol/L ∙ s (d) 4.96 × 10−5 mol/L ∙ s

Interpretation Introduction

Interpretation:

The rate of the reaction should be identified.

Concept introduction:

The Reaction Rate for a given chemical reaction is the measure of the change in concentration of the reactants or the change in concentration of the products per unit time.

### Explanation of Solution

(a)

The given reaction is shown below,

NO(g)+12Cl2(g)NOCl(g)

First order is Cl2 and second order is NO. Therefore,

The rate of the reaction is,

rate=K[NO]2[Cl2]1

rate=K[NO]2[Cl2]1K=6.20×10-6iftheconcentrationisdoubled,[NO]=2[NO]theconcentration&#

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