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A solution of 0.312 M KOH is used to titrate
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Chapter 14 Solutions
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- 1. Sometimes a reaction can fall in more than one category. Into what category (or categories) does the reaction of Ba(OH)2(aq) + H+PO4(aq) fit? acid-base and oxidation-reduction oxidation-reduction acid-base and precipitation precipitationarrow_forward2. Equal amounts (moles) of acetic acid(aq) and sodium sulfite, Na2SO3(aq), are mixed. The resulting solution is acidic basic neutralarrow_forwardArsenic acid, H3AsO4, is a poisonous acid that has been used in the treatment of wood to prevent insect damage. Arsenic acid has three acidic protons. Say you take a 25.00-mL sample of arsenic acid and prepare it for titration with NaOH by adding 25.00 mL of water. The complete neutralization of this solution requires the addition of 53.07 mL of 0.6441 M NaOH solution. Write the balanced chemical reaction for the titration, and calculate the molarity of the arsenic acid sample.arrow_forward
- A soluble iodide was dissolved in water. Then an excess of silver nitrate, AgNO3, was added to precipitate all of the iodide ion as silver iodide, AgI. If 1.545 g of the soluble iodide gave 2.185 g of silver iodide, how many grams of iodine are in the sample of soluble iodide? What is the mass percentage of iodine, I, in the compound?arrow_forwardA 25.0-mL sample of vinegar (which contains the weak acid acetic acid, CH3CO2H) requires 28.33 mL of a 0.953 M solution of NaOH for titration to the equivalence point. What is the mass of acetic acid (molar mass = 60.05 g/mol), in grams, in the vinegar sample, and what is the concentration of acetic acid in the vinegar? CH3CO2H(aq) + NaOH(aq) NaCH3CO2(aq) + H2O(l)arrow_forwardFor a product to be called vinegar, it must contain at least 5.0% acetic acid, HC2H3O2, by mass. A 10.00-g sample of a raspberry vinegar is titrated with 0.1250 M Ba(OH)2 and required 37.50 mL for complete neutralization. Can the product be called a vinegar?arrow_forward
- A 0.608-g sample of fertilizer contained nitrogen as ammonium sulfate, (NH4)2SO4. It was analyzed for nitrogen by heating with sodium hydroxide. (NH4)2SO4(s)+2NaOH(aq)Na2SO4(aq)+2H2O(l)+2NH3(g) The ammonia was collected in 46.3 mL of 0.213 M HCl (hydrochloric acid), with which it reacted. NH3(g)+HCl(aq)NH4Cl(aq) This solution was titrated for excess hydrochloric acid with 44.3 mL of 0.128 M NaOH. NaOH(aq)+HCl(aq)NaCl(aq)+H2O(l) What is the percentage of nitrogen in the fertilizer?arrow_forwardWhat is the molar concentration of an H2SO4 solution if a 50.0-mL sample requires 9.65 mL of a 1.33 M solution of NaOH to reach the equivalence point?arrow_forwardAn antacid tablet contains sodium hydrogen carbonate, NaHCO3, and inert ingredients. A 0.465-g sample of powdered tablet was mixed with 53.3 mL of 0.190 M HCl (hydrochloric acid). The mixture was allowed to stand until it reacted. NaHCO3(s)+HCl(aq)NaCl(aq)+H2O(l)+CO2(g) The excess hydrochloric acid was titrated with 54.6 mL of 0.128 M NaOH (sodium hydroxide). HCl(aq)+NaOH(aq)NaCl(aq)+H2O(l) What is the percentage of sodium hydrogen carbonate in the antacid?arrow_forward
- Oranges and grapefruits are known as citrus fruits because their acidity comes mainly from citric acid, H3C6H5O7. Calculate the concentration of citric acid in a solution if a 30.00-mL sample is neutralized by 15.10 mL of 0.0100 M KOH. Assume that three acidic hydrogens of each citric acid molecule are neutralized in the reaction.arrow_forwardPotassium permanganate (KMnO4) solutions are used for the determination of Fe2+ in samples of unknown concentration. As a laboratory assistant, you are supposed to prepare 500 mL of a 0.1000 M KMnO4 solution. What mass of KMnO4, in grams, do you need?arrow_forwardA 1.345-g sample of a compound of barium and oxygen was dissolved in hydrochloric acid to give a solution of barium ion, which was then precipitated with an excess of potassium chromate to give 2.012 g of barium chromate, BaCrO4. What is the formula of the compound?arrow_forward
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