   Chapter 15, Problem 106AP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
1 views

# A certain grade of steel is made by dissolving 5.0 g of carbon and 1.5 g of nickel per 100. g of molten iron. What is the mass percent of each component in the finished steel?

Interpretation Introduction

Interpretation:

The mass percentage of each component in the finished steel is to be calculated.

Concept Introduction:

The mass percentage of a component present in a mixture is calculated by dividing the mass of the component present in the mixture by the total mass of the mixture and then multiplying it by 100. The formula for mass percentage is represented as:

mass%=MMt×100%

Where,

• M represents the mass of the component present in the mixture.
• Mt represents the total mass of mixture.
Explanation

The mass of carbon in the steel is 5.0g.

The mass of nickel in the steel is 1.5g.

The mass of iron in the steel is 100.0g.

The formula for mass percentage is given as:

mass%=MMt×100%

Where,

• M represents the mass of the component present in the mixture.
• Mt represents the total mass of mixture.

The total mass of the steel is given as:

Mt=MC+MNi+MFe

Where,

• MC represents the mass of carbon in the steel.
• MNi represents the mass of nickel in the steel.
• MFe represents the mass of iron in the steel.

Substitute the value of mass of carbon, nickel and iron in the above equation.

Mt=5.0g+1.5g+100.0g=106.5g

The total mass of the steel is 106.5g

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