   Chapter 15, Problem 139CP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
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# What volume of 0.100 M NaOH is required to precipitate all of the nickel(II) ions from 150.0 mL of a 0.249 M solution of Ni( NO3)2?

Interpretation Introduction

Interpretation:

The volume of 0.100MNaOH required to precipitate all of the nickelII ions from 150.0mL of a 0.249M solution of NiNO32 is to be calculated.

Concept Introduction:

The molarity of a solution is defined as the number of moles of solute dissolved in one liter of the solution. The formula for molarity is given as,

M=nV

Where,

• n represents the number of moles of the solute.
• V represents the volume of the solution.
Explanation

The molarity of the given NaOH solution is 0.100M.

The molarity of the given NiNO32 solution is 0.249M.

The volume of the given NiNO32 solution is 150.0mL.

The reaction between NaOH and NiNO32 is represented as:

2NaOHaq+NiNO32aqNiOH2s+2NaNO3aq

The relation between molarities of NaOH and NiNO32 is given as:

M1V1=2M2V2

Where,

• M1 represents the molarity of NaOH.
• V1 represents the volume of NaOH

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