   Chapter 15, Problem 14ALQ ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
2287 views

# The drawings below represent aqueous solutions. Solution A is ola 2.00 M aqueous solution of copper(II) nitrate. Solution B is 2.00 L of a 3.00 M aqueous solution of potassium hydroxide. mg src=Images/HTML_99425-15-14ALQ_image001.jpg alt="" align="top"/> Draw a picture of the solution made by mixing solutions A and B together after the precipitation reaction takes place. Make sure this picture shows the correct relative volume compared to solutions A and B and the correct relative number of ions, along with the correct relative amount of solid formed. Determine the concentrations (in M) of all ions left in solution (from part a) and the mass of solid formed.

Interpretation Introduction

(a)

Interpretation:

The picture of the solution made by mixing solution A and B together after the precipitation reaction takes place is to be drawn.

Concept Introduction:

The molarity of a solution is the molar concentration of the solution; it measures the number of moles of solute dissolved in one liter of the solution. The formula for molarity is given as,

M=nV

Where,

• n represents the number of moles of the solute.
• V represents the volume of the solution.

The limiting reagent of a reaction is that reactant of the reaction that controls the amount of product formed. The amount of a limiting reagent is lower than its required amount to complete the reaction.

Explanation

The volume of 2.00M

copperII nitrate solution is 2.00L.

The volume of 3.00M potassium hydroxide solution is 2.00L.

The molarity of a solution is given as,

M=nV    (1)

Where,

• n represents the number of moles of the solute.
• V represents the volume of the solution.

Rearrange the above equation for the value of n.

n=MV    (2)

Substitute the value of molarity and volume of copperII nitrate solution in equation (2).

n=2.00M1molL11M2.00L=4.00mol

The number of moles of copperII nitrate present in the reaction mixture is 4.00mol.

Substitute the value of molarity and volume of potassium hydroxide solution in equation (2).

n=3.00M1molL11M2.00L=6.00mol

The number of moles of potassium hydroxide present in the reaction mixture is 6.00mol.

The balance chemical reaction between copperII nitrate and potassium hydroxide is represented as,

CuNO32aq+2KOHaqCuOH2s+2KNO3aq

The complete ionic reaction between copperII nitrate and potassium hydroxide is represented as,

Cu2+aq+2NO3aq+2K+aq+2OH<

Interpretation Introduction

(b)

Interpretation:

The concentration of all ions left in solution after completion of the reaction and mass of the solid formed is to be calculated.

Concept Introduction:

The molarity of a solution is the molar concentration of the solution; it measures the number of moles of solute dissolved in one liter of the solution. The formula for molarity is given as,

M=nV

Where,

• n represents the number of moles of the solute.
• V represents the volume of the solution.

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