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General Chemistry - Standalone boo...

11th Edition
Steven D. Gammon + 7 others
ISBN: 9781305580343

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BuyFindarrow_forward

General Chemistry - Standalone boo...

11th Edition
Steven D. Gammon + 7 others
ISBN: 9781305580343
Textbook Problem

A 2.500-g sample of a mixture of sodium carbonate and sodium chloride is dissolved in 25.00 mL of 0.798 M HCl. Some acid remains after the treatment of the sample.

  1. a Write the net ionic equation for the complete reaction of sodium carbonate with hydrochloric acid
  2. b If 28.7 mL of 0.108 M NaOH were required to titrate the excess hydrochloric acid, how many moles of sodium carbonate were present in the original sample?
  3. c What is the percent composition of the original sample?

(a)

Interpretation Introduction

Interpretation:

The explanations for the given set of statements have to be given.

Concept introduction:

The percent composition of the given original sample can be calculated by using the following formula.

percent composition = mol NaHCO3×g NaHCO31 mol NaHCO3

Explanation

The complete reaction of sodium carbonate with hydrochloric acid is

CO32-(aq) + 2H3O

(b)

Interpretation Introduction

Interpretation:

The explanations for the given set of statements have to be given.

Concept introduction:

The percent composition of the given original sample can be calculated by using the following formula.

percent composition = mol NaHCO3×g NaHCO31 mol NaHCO3

(c)

Interpretation Introduction

Interpretation:

The explanations for the given set of statements have to be given.

Concept introduction:

The percent composition of the given original sample can be calculated by using the following formula.

percent composition = mol NaHCO3×g NaHCO31 mol NaHCO3

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Chapter 15 Solutions

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Sect-15.8 P-15.8ESect-15.8 P-15.9ESect-15.8 P-15.10ESect-15.8 P-15.4CCCh-15 P-15.1QPCh-15 P-15.2QPCh-15 P-15.3QPCh-15 P-15.4QPCh-15 P-15.5QPCh-15 P-15.6QPCh-15 P-15.7QPCh-15 P-15.8QPCh-15 P-15.9QPCh-15 P-15.10QPCh-15 P-15.11QPCh-15 P-15.12QPCh-15 P-15.13QPCh-15 P-15.14QPCh-15 P-15.15QPCh-15 P-15.16QPCh-15 P-15.17QPCh-15 P-15.18QPCh-15 P-15.19QPCh-15 P-15.20QPCh-15 P-15.21QPCh-15 P-15.22QPCh-15 P-15.23QPCh-15 P-15.24QPCh-15 P-15.25QPCh-15 P-15.26QPCh-15 P-15.27QPCh-15 P-15.28QPCh-15 P-15.29QPCh-15 P-15.30QPCh-15 P-15.31QPCh-15 P-15.32QPCh-15 P-15.33QPCh-15 P-15.34QPCh-15 P-15.35QPCh-15 P-15.36QPCh-15 P-15.37QPCh-15 P-15.38QPCh-15 P-15.39QPCh-15 P-15.40QPCh-15 P-15.41QPCh-15 P-15.42QPCh-15 P-15.43QPCh-15 P-15.44QPCh-15 P-15.45QPCh-15 P-15.46QPCh-15 P-15.47QPCh-15 P-15.48QPCh-15 P-15.49QPCh-15 P-15.50QPCh-15 P-15.51QPCh-15 P-15.52QPCh-15 P-15.53QPCh-15 P-15.54QPCh-15 P-15.55QPCh-15 P-15.56QPCh-15 P-15.57QPCh-15 P-15.58QPCh-15 P-15.59QPCh-15 P-15.60QPCh-15 P-15.61QPCh-15 P-15.62QPCh-15 P-15.63QPCh-15 P-15.64QPCh-15 P-15.65QPCh-15 P-15.66QPCh-15 P-15.67QPCh-15 P-15.68QPCh-15 P-15.69QPCh-15 P-15.70QPCh-15 P-15.71QPCh-15 P-15.72QPCh-15 P-15.73QPCh-15 P-15.74QPCh-15 P-15.75QPCh-15 P-15.76QPCh-15 P-15.77QPCh-15 P-15.78QPCh-15 P-15.79QPCh-15 P-15.80QPCh-15 P-15.81QPCh-15 P-15.82QPCh-15 P-15.83QPCh-15 P-15.84QPCh-15 P-15.85QPCh-15 P-15.86QPCh-15 P-15.87QPCh-15 P-15.88QPCh-15 P-15.89QPCh-15 P-15.90QPCh-15 P-15.91QPCh-15 P-15.92QPCh-15 P-15.93QPCh-15 P-15.94QPCh-15 P-15.95QPCh-15 P-15.96QPCh-15 P-15.97QPCh-15 P-15.98QPCh-15 P-15.99QPCh-15 P-15.100QPCh-15 P-15.101QPCh-15 P-15.102QPCh-15 P-15.103QPCh-15 P-15.104QPCh-15 P-15.105QPCh-15 P-15.106QPCh-15 P-15.107QPCh-15 P-15.108QPCh-15 P-15.109QPCh-15 P-15.110QPCh-15 P-15.111QPCh-15 P-15.112QPCh-15 P-15.113QPCh-15 P-15.114QPCh-15 P-15.115QPCh-15 P-15.116QPCh-15 P-15.117QPCh-15 P-15.118QPCh-15 P-15.119QPCh-15 P-15.120QPCh-15 P-15.121QPCh-15 P-15.122QPCh-15 P-15.123QPCh-15 P-15.124QPCh-15 P-15.125QPCh-15 P-15.126QPCh-15 P-15.127QPCh-15 P-15.128QPCh-15 P-15.129QPCh-15 P-15.130QPCh-15 P-15.131QPCh-15 P-15.132QP

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