General Chemistry
General Chemistry
4th Edition
ISBN: 9781891389603
Author: Donald A. McQuarrie, Peter A. Rock, Ethan B. Gallogly
Publisher: University Science Books
bartleby

Concept explainers

bartleby

Videos

Question
Chapter 15, Problem 15.1P
Interpretation Introduction

Interpretation:

The heat energy required to vaporize 5kg of ammonia molecule has to be determined.

Concept Introduction:

Molar enthalpy for a process is the quantity of heat energy needed by one mole of a substance to undergo change in the process. The heat energy absorbed by n moles of substance to undergo change is as follows:

  q=n(ΔH)

Here,

q is the heat energy in kJ

n is the number of moles of substance.

ΔH is the enthalpy for process in kJ/mol .

The value of ΔH is positive always as energy is needed to overcome the interactions between the liquid molecules.

Expert Solution & Answer
Check Mark

Answer to Problem 15.1P

The heat energy required to vaporize 5kg of ammonia molecule is 6849.2727kJ.

Explanation of Solution

The formula to determine moles of ammonia is as follows:

  numberofmolesofammonia=massofammoniamolecularweightofammonia        (1)

Substitute 17.031g/mol for molecular weight of ammonia, 5kg for mass of ammonia in equation (1).

  numberofmolesofammonia=5kg(1000g1kg)17.031g/mol=293.5822mol

The formula for heat energy required to vaporize 5kg of ammonia molecule is as follows:

  qvap=n(ΔHvap)        (2)

Substitute 23.33kJ/mol for ΔHvap and 293.5822mol for n in equation (2) to calculate the heat energy required to vaporize 5kg of ammonia molecule.

  qvap=(293.5822mol)(23.33kJ/mol)=6849.2727kJ

The heat energy needed to vaporize 5kg of ammonia molecule is 6849.2727kJ.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Chapter 15 Solutions

General Chemistry

Knowledge Booster
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Recommended textbooks for you
  • Chemistry
    Chemistry
    ISBN:9781305957404
    Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
    Publisher:Cengage Learning
    Chemistry
    Chemistry
    ISBN:9781259911156
    Author:Raymond Chang Dr., Jason Overby Professor
    Publisher:McGraw-Hill Education
    Principles of Instrumental Analysis
    Chemistry
    ISBN:9781305577213
    Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
    Publisher:Cengage Learning
  • Organic Chemistry
    Chemistry
    ISBN:9780078021558
    Author:Janice Gorzynski Smith Dr.
    Publisher:McGraw-Hill Education
    Chemistry: Principles and Reactions
    Chemistry
    ISBN:9781305079373
    Author:William L. Masterton, Cecile N. Hurley
    Publisher:Cengage Learning
    Elementary Principles of Chemical Processes, Bind...
    Chemistry
    ISBN:9781118431221
    Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
    Publisher:WILEY
  • Chemistry
    Chemistry
    ISBN:9781305957404
    Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
    Publisher:Cengage Learning
    Chemistry
    Chemistry
    ISBN:9781259911156
    Author:Raymond Chang Dr., Jason Overby Professor
    Publisher:McGraw-Hill Education
    Principles of Instrumental Analysis
    Chemistry
    ISBN:9781305577213
    Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
    Publisher:Cengage Learning
    Organic Chemistry
    Chemistry
    ISBN:9780078021558
    Author:Janice Gorzynski Smith Dr.
    Publisher:McGraw-Hill Education
    Chemistry: Principles and Reactions
    Chemistry
    ISBN:9781305079373
    Author:William L. Masterton, Cecile N. Hurley
    Publisher:Cengage Learning
    Elementary Principles of Chemical Processes, Bind...
    Chemistry
    ISBN:9781118431221
    Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
    Publisher:WILEY
    Types of Matter: Elements, Compounds and Mixtures; Author: Professor Dave Explains;https://www.youtube.com/watch?v=dggHWvFJ8Xs;License: Standard YouTube License, CC-BY