Complete the following summary of Morgan’s crosses involving the mutant white-eyed fly by filling in the Punnett square and indicating the genotypes and phenotypes of the F 2 generation. (X w stands for the mutant recessive white allele; X w + for the wild-type red allele.) The Y reminds you that this eye color gene is not present on the Y chromosome. Genotypes ___ _ _ _ Phenotypes _ _ _ ___

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Answer 1

Textbook Question

Chapter 15, Problem 1IQ

Complete the following summary of Morgan’s crosses involving the mutant white-eyed fly by filling in the Punnett square and indicating the genotypes and phenotypes of the F₂ generation. (X^w stands for the mutant recessive white allele; X^w⁺ for the wild-type red allele.) The Y reminds you that this eye color gene is not present on the Y chromosome.

Chapter 15, Problem 1IQ, Complete the following summary of Morgans crosses involving the mutant white-eyed fly by filling in

Genotypes

_____ _____ _____ _____

Phenotypes

_____ _____ _____ _____

Expert Solution & Answer

Summary Introduction

To complete: The summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Introduction: Sex chromosomes are those chromosomes that play a crucial role in determination of sex of the individual. They have important function in the development of sexual characteristics in the organisms.

Answer to Problem 1IQ

Pictorial representation: Fig.1 represents the summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Study Guide for Campbell Biology, Chapter 15, Problem 1IQ

Fig.1: Morgan’s cross of mutant white-eyed fly with the genotypes and phenotypes of the F₂ generation

Explanation of Solution

The X and Y chromosomes act as sex chromosomes in most of the organisms. The genes that are present on the sex chromosome are called sex-linked genes. There are approximately 1,100 X-linked genes. On the other hand, Y chromosome contains relatively very few genes.

The sex-linked genes display a unique pattern of inheritance. The expression of recessive X-linked trait requires two copies of alleles in females (homozygous) and only one copy of the allele in males (hemizygous). The probability of a male to receive a single mutated X-linked gene from their mother is high as compared to a female receiving both the X-linked mutated genes from the mother (carrier) and father (carrier).

When Morgan crossed red-eyed female (wild-type) with white-eyed male (mutant), all the offspring were red-eyed in the first generation (F₁). Then, he again crossed the F₁red-eyed female to the red-eyed male of F₁. The typical ratio of 3:1 (red-eyed flies: white eyed flies) was observed in the F₂ generation, but all white-eyed flies were males.

Morgan concluded that this could be due to hemizygous condition (presence of single X-chromosome “X^W+Y”) of the males. Females required both the mutated alleles to express the phenotype (white eye color), while males needed only one mutated allele to show the phenotype. The probability to inherit both mutated copies is less.

Hence, four genotypes of F₂ generation are as follows:

X^W+X^W+
X^W+X^W
X^W+Y
X^WY

The four phenotypes of F₂ generation are as follows:

Red-eyed female
Red-eyed female
Red-eyed male
White-eyed male.

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03:46

Students have asked these similar questions

A mother is heterozygous for the X-linked gene for colorblindness and also heterozygous for the autosomal inherited sickle cell anemia. She is married to a man who can see color normally and who is heterozygous for sickle cell trait. Using b (colorblind), B (normal color), S (normal hemoglobin), s (sickle cell), answer the following: a. What are the genotypes of the parents? b: What is the probability of having a child who is both color blind and has sickle cell anemia?

Greg is color blind and marries Susan, who is a carrier for color blindness. Color blindness is an X-linked, genetic trait. Draw the Punnett square for their children. Label each individual in the chart with their actual or predicted genotype. Fill input: Fill input: Fill input: Fill input: Fill input: Fill input: Fill input: Fill input: XX X Xy y xy X Xx Is there any chance they could have a son who is not color blind? If so, what is the probability of Greg and Susan having a son with normal vision? What is the probability of Greg and Susan having a color-blind daughter?

For the Y-linked gene, use T for hypertrichosis. For X-linked genes, use the letters H for blood trait and E for eye trait. Krisha, a carrier of the genes for hemophilia and colorblindness, is married to Kyle who is color blind, having normal red blood cells. Veronica (Krisha & Kyle's daughter), turned out to be a carrier for both genes. Julian has hypertrichosis and is married to Josie. Both do not exhibit any allele for color blindness and never had any history for hemophilia. Bernard (Julian & Josie's son) will be married to Veronica. What are the complete genotypes of the following persons: a. Krisha b. Kyle c. Veronica d. Julian e. Josie f. Bernard g. Josie & Bernard's baby

Answer 2

Textbook Question

Chapter 15, Problem 1IQ

Complete the following summary of Morgan’s crosses involving the mutant white-eyed fly by filling in the Punnett square and indicating the genotypes and phenotypes of the F₂ generation. (X^w stands for the mutant recessive white allele; X^w⁺ for the wild-type red allele.) The Y reminds you that this eye color gene is not present on the Y chromosome.

Chapter 15, Problem 1IQ, Complete the following summary of Morgans crosses involving the mutant white-eyed fly by filling in

Genotypes

_____ _____ _____ _____

Phenotypes

_____ _____ _____ _____

Expert Solution & Answer

Summary Introduction

To complete: The summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Introduction: Sex chromosomes are those chromosomes that play a crucial role in determination of sex of the individual. They have important function in the development of sexual characteristics in the organisms.

Answer to Problem 1IQ

Pictorial representation: Fig.1 represents the summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Study Guide for Campbell Biology, Chapter 15, Problem 1IQ

Fig.1: Morgan’s cross of mutant white-eyed fly with the genotypes and phenotypes of the F₂ generation

Explanation of Solution

The X and Y chromosomes act as sex chromosomes in most of the organisms. The genes that are present on the sex chromosome are called sex-linked genes. There are approximately 1,100 X-linked genes. On the other hand, Y chromosome contains relatively very few genes.

The sex-linked genes display a unique pattern of inheritance. The expression of recessive X-linked trait requires two copies of alleles in females (homozygous) and only one copy of the allele in males (hemizygous). The probability of a male to receive a single mutated X-linked gene from their mother is high as compared to a female receiving both the X-linked mutated genes from the mother (carrier) and father (carrier).

When Morgan crossed red-eyed female (wild-type) with white-eyed male (mutant), all the offspring were red-eyed in the first generation (F₁). Then, he again crossed the F₁red-eyed female to the red-eyed male of F₁. The typical ratio of 3:1 (red-eyed flies: white eyed flies) was observed in the F₂ generation, but all white-eyed flies were males.

Morgan concluded that this could be due to hemizygous condition (presence of single X-chromosome “X^W+Y”) of the males. Females required both the mutated alleles to express the phenotype (white eye color), while males needed only one mutated allele to show the phenotype. The probability to inherit both mutated copies is less.

Hence, four genotypes of F₂ generation are as follows:

X^W+X^W+
X^W+X^W
X^W+Y
X^WY

The four phenotypes of F₂ generation are as follows:

Red-eyed female
Red-eyed female
Red-eyed male
White-eyed male.

Want to see more full solutions like this?

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03:46

Answer 3

Textbook Question

Chapter 15, Problem 1IQ

Complete the following summary of Morgan’s crosses involving the mutant white-eyed fly by filling in the Punnett square and indicating the genotypes and phenotypes of the F₂ generation. (X^w stands for the mutant recessive white allele; X^w⁺ for the wild-type red allele.) The Y reminds you that this eye color gene is not present on the Y chromosome.

Chapter 15, Problem 1IQ, Complete the following summary of Morgans crosses involving the mutant white-eyed fly by filling in

Genotypes

_____ _____ _____ _____

Phenotypes

_____ _____ _____ _____

Expert Solution & Answer

Summary Introduction

To complete: The summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Introduction: Sex chromosomes are those chromosomes that play a crucial role in determination of sex of the individual. They have important function in the development of sexual characteristics in the organisms.

Answer to Problem 1IQ

Pictorial representation: Fig.1 represents the summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Study Guide for Campbell Biology, Chapter 15, Problem 1IQ

Fig.1: Morgan’s cross of mutant white-eyed fly with the genotypes and phenotypes of the F₂ generation

Explanation of Solution

The X and Y chromosomes act as sex chromosomes in most of the organisms. The genes that are present on the sex chromosome are called sex-linked genes. There are approximately 1,100 X-linked genes. On the other hand, Y chromosome contains relatively very few genes.

The sex-linked genes display a unique pattern of inheritance. The expression of recessive X-linked trait requires two copies of alleles in females (homozygous) and only one copy of the allele in males (hemizygous). The probability of a male to receive a single mutated X-linked gene from their mother is high as compared to a female receiving both the X-linked mutated genes from the mother (carrier) and father (carrier).

When Morgan crossed red-eyed female (wild-type) with white-eyed male (mutant), all the offspring were red-eyed in the first generation (F₁). Then, he again crossed the F₁red-eyed female to the red-eyed male of F₁. The typical ratio of 3:1 (red-eyed flies: white eyed flies) was observed in the F₂ generation, but all white-eyed flies were males.

Morgan concluded that this could be due to hemizygous condition (presence of single X-chromosome “X^W+Y”) of the males. Females required both the mutated alleles to express the phenotype (white eye color), while males needed only one mutated allele to show the phenotype. The probability to inherit both mutated copies is less.

Hence, four genotypes of F₂ generation are as follows:

X^W+X^W+
X^W+X^W
X^W+Y
X^WY

The four phenotypes of F₂ generation are as follows:

Red-eyed female
Red-eyed female
Red-eyed male
White-eyed male.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

03:46

Answer 4

Textbook Question

Chapter 15, Problem 1IQ

Complete the following summary of Morgan’s crosses involving the mutant white-eyed fly by filling in the Punnett square and indicating the genotypes and phenotypes of the F₂ generation. (X^w stands for the mutant recessive white allele; X^w⁺ for the wild-type red allele.) The Y reminds you that this eye color gene is not present on the Y chromosome.

Chapter 15, Problem 1IQ, Complete the following summary of Morgans crosses involving the mutant white-eyed fly by filling in

Genotypes

_____ _____ _____ _____

Phenotypes

_____ _____ _____ _____

Expert Solution & Answer

Summary Introduction

To complete: The summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Introduction: Sex chromosomes are those chromosomes that play a crucial role in determination of sex of the individual. They have important function in the development of sexual characteristics in the organisms.

Answer to Problem 1IQ

Pictorial representation: Fig.1 represents the summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Study Guide for Campbell Biology, Chapter 15, Problem 1IQ

Fig.1: Morgan’s cross of mutant white-eyed fly with the genotypes and phenotypes of the F₂ generation

Explanation of Solution

The X and Y chromosomes act as sex chromosomes in most of the organisms. The genes that are present on the sex chromosome are called sex-linked genes. There are approximately 1,100 X-linked genes. On the other hand, Y chromosome contains relatively very few genes.

The sex-linked genes display a unique pattern of inheritance. The expression of recessive X-linked trait requires two copies of alleles in females (homozygous) and only one copy of the allele in males (hemizygous). The probability of a male to receive a single mutated X-linked gene from their mother is high as compared to a female receiving both the X-linked mutated genes from the mother (carrier) and father (carrier).

When Morgan crossed red-eyed female (wild-type) with white-eyed male (mutant), all the offspring were red-eyed in the first generation (F₁). Then, he again crossed the F₁red-eyed female to the red-eyed male of F₁. The typical ratio of 3:1 (red-eyed flies: white eyed flies) was observed in the F₂ generation, but all white-eyed flies were males.

Morgan concluded that this could be due to hemizygous condition (presence of single X-chromosome “X^W+Y”) of the males. Females required both the mutated alleles to express the phenotype (white eye color), while males needed only one mutated allele to show the phenotype. The probability to inherit both mutated copies is less.

Hence, four genotypes of F₂ generation are as follows:

X^W+X^W+
X^W+X^W
X^W+Y
X^WY

The four phenotypes of F₂ generation are as follows:

Red-eyed female
Red-eyed female
Red-eyed male
White-eyed male.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

03:46

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution & Answer

Summary Introduction

To complete: The summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Introduction: Sex chromosomes are those chromosomes that play a crucial role in determination of sex of the individual. They have important function in the development of sexual characteristics in the organisms.

Answer to Problem 1IQ

Pictorial representation: Fig.1 represents the summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Study Guide for Campbell Biology, Chapter 15, Problem 1IQ

Fig.1: Morgan’s cross of mutant white-eyed fly with the genotypes and phenotypes of the F₂ generation

Explanation of Solution

The X and Y chromosomes act as sex chromosomes in most of the organisms. The genes that are present on the sex chromosome are called sex-linked genes. There are approximately 1,100 X-linked genes. On the other hand, Y chromosome contains relatively very few genes.

The sex-linked genes display a unique pattern of inheritance. The expression of recessive X-linked trait requires two copies of alleles in females (homozygous) and only one copy of the allele in males (hemizygous). The probability of a male to receive a single mutated X-linked gene from their mother is high as compared to a female receiving both the X-linked mutated genes from the mother (carrier) and father (carrier).

When Morgan crossed red-eyed female (wild-type) with white-eyed male (mutant), all the offspring were red-eyed in the first generation (F₁). Then, he again crossed the F₁red-eyed female to the red-eyed male of F₁. The typical ratio of 3:1 (red-eyed flies: white eyed flies) was observed in the F₂ generation, but all white-eyed flies were males.

Morgan concluded that this could be due to hemizygous condition (presence of single X-chromosome “X^W+Y”) of the males. Females required both the mutated alleles to express the phenotype (white eye color), while males needed only one mutated allele to show the phenotype. The probability to inherit both mutated copies is less.

Hence, four genotypes of F₂ generation are as follows:

X^W+X^W+
X^W+X^W
X^W+Y
X^WY

The four phenotypes of F₂ generation are as follows:

Red-eyed female
Red-eyed female
Red-eyed male
White-eyed male.

Answer 8

Expert Solution & Answer

Summary Introduction

To complete: The summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Introduction: Sex chromosomes are those chromosomes that play a crucial role in determination of sex of the individual. They have important function in the development of sexual characteristics in the organisms.

Answer to Problem 1IQ

Pictorial representation: Fig.1 represents the summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Study Guide for Campbell Biology, Chapter 15, Problem 1IQ

Fig.1: Morgan’s cross of mutant white-eyed fly with the genotypes and phenotypes of the F₂ generation

Explanation of Solution

The X and Y chromosomes act as sex chromosomes in most of the organisms. The genes that are present on the sex chromosome are called sex-linked genes. There are approximately 1,100 X-linked genes. On the other hand, Y chromosome contains relatively very few genes.

The sex-linked genes display a unique pattern of inheritance. The expression of recessive X-linked trait requires two copies of alleles in females (homozygous) and only one copy of the allele in males (hemizygous). The probability of a male to receive a single mutated X-linked gene from their mother is high as compared to a female receiving both the X-linked mutated genes from the mother (carrier) and father (carrier).

When Morgan crossed red-eyed female (wild-type) with white-eyed male (mutant), all the offspring were red-eyed in the first generation (F₁). Then, he again crossed the F₁red-eyed female to the red-eyed male of F₁. The typical ratio of 3:1 (red-eyed flies: white eyed flies) was observed in the F₂ generation, but all white-eyed flies were males.

Morgan concluded that this could be due to hemizygous condition (presence of single X-chromosome “X^W+Y”) of the males. Females required both the mutated alleles to express the phenotype (white eye color), while males needed only one mutated allele to show the phenotype. The probability to inherit both mutated copies is less.

Hence, four genotypes of F₂ generation are as follows:

X^W+X^W+
X^W+X^W
X^W+Y
X^WY

The four phenotypes of F₂ generation are as follows:

Red-eyed female
Red-eyed female
Red-eyed male
White-eyed male.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Summary Introduction

To complete: The summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Introduction: Sex chromosomes are those chromosomes that play a crucial role in determination of sex of the individual. They have important function in the development of sexual characteristics in the organisms.

Answer 12

Answer to Problem 1IQ

Pictorial representation: Fig.1 represents the summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Study Guide for Campbell Biology, Chapter 15, Problem 1IQ

Fig.1: Morgan’s cross of mutant white-eyed fly with the genotypes and phenotypes of the F₂ generation

Answer 13

Explanation of Solution

The X and Y chromosomes act as sex chromosomes in most of the organisms. The genes that are present on the sex chromosome are called sex-linked genes. There are approximately 1,100 X-linked genes. On the other hand, Y chromosome contains relatively very few genes.

The sex-linked genes display a unique pattern of inheritance. The expression of recessive X-linked trait requires two copies of alleles in females (homozygous) and only one copy of the allele in males (hemizygous). The probability of a male to receive a single mutated X-linked gene from their mother is high as compared to a female receiving both the X-linked mutated genes from the mother (carrier) and father (carrier).

When Morgan crossed red-eyed female (wild-type) with white-eyed male (mutant), all the offspring were red-eyed in the first generation (F₁). Then, he again crossed the F₁red-eyed female to the red-eyed male of F₁. The typical ratio of 3:1 (red-eyed flies: white eyed flies) was observed in the F₂ generation, but all white-eyed flies were males.

Morgan concluded that this could be due to hemizygous condition (presence of single X-chromosome “X^W+Y”) of the males. Females required both the mutated alleles to express the phenotype (white eye color), while males needed only one mutated allele to show the phenotype. The probability to inherit both mutated copies is less.

Hence, four genotypes of F₂ generation are as follows:

X^W+X^W+
X^W+X^W
X^W+Y
X^WY

The four phenotypes of F₂ generation are as follows:

Red-eyed female
Red-eyed female
Red-eyed male
White-eyed male.

Answer 14

Ch. 15 - Complete the following summary of Morgans crosses...Ch. 15 - Two normal color-sighted individuals have two...Ch. 15 - In a testcross between a heterozygote tall,...Ch. 15 - With unlinked genes, an equal number of parental...Ch. 15 - The following recombination frequencies have been...Ch. 15 - a. What is the difference between an organism with...Ch. 15 - Prob. 7IQ Ch. 15 - Prob. 8IQ Ch. 15 - Mendels law of independent assortment applies to...Ch. 15 - You have found a new mutant phenotype in fruit...

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Answer to Problem 1IQ

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