   Chapter 15, Problem 21E

Chapter
Section
Textbook Problem

# Calculate the pH of each of the following solutions.a. 0.100 M propanoic acid (HC3H5O2, Ka = 1.3 × 10−5)b. 0.100 M sodium propanoate (NaC3H5O2)c. pure H2Od. a mixture containing 0.100 M HC3H5O2 and 0.100 M NaC3H5O2

(a)

Interpretation Introduction

Interpretation:

The pH of the given solutions is to be calculated.

Concept introduction:

The pH of a solution is define as a figure that expresses the acidity of the alkalinity of a given solution.

The pH of a solution is calculated by the formula, pH=log[H+]

The sum, pH+pOH=14

The value of Kw is calculated by the formula,

Kw=KaKb

Explanation

Explanation

To determine The [H+] in the given solution.

The reaction that takes place in the given case is,

HC3H5O2(aq)+H2O(l)H3O+(aq)+C3H5O2(aq)

The change in the concentration of HC3H5O2 is assumed to be x .

The ICE table is formed for the given reaction.

HC3H5O2(aq)H+(aq)+C3H5O2(aq)Initialconcentration0.10000Changex+x+xEquilibriumconcentration0.100xxx

The equilibrium concentration of [HC3H5O2] is (0.100x)M .

The equilibrium concentration of [C3H5O2] is xM .

The equilibrium concentration of [H+] is xM .

At equilibrium, the equilibrium constant expression is expressed by the formula,

Ka=ConcentrationofproductsConcentrationofreactants

Where,

• Ka is the acid dissociation constant.

The equilibrium constant expression for the given reaction is,

Ka=[C3H5O2][H+][HC3H5O2]

The value of Ka is given to be 1

(b)

Interpretation Introduction

Interpretation:

The pH of the given solutions is to be calculated.

Concept introduction:

The pH of a solution is define as a figure that expresses the acidity of the alkalinity of a given solution.

The pH of a solution is calculated by the formula, pH=log[H+]

The sum, pH+pOH=14

The value of Kw is calculated by the formula,

Kw=KaKb

(c)

Interpretation Introduction

Interpretation:

The pH of the given solutions is to be calculated.

Concept introduction:

The pH of a solution is define as a figure that expresses the acidity of the alkalinity of a given solution.

The pH of a solution is calculated by the formula, pH=log[H+]

The sum, pH+pOH=14

The value of Kw is calculated by the formula,

Kw=KaKb

(d)

Interpretation Introduction

Interpretation:

The pH of the given solutions is to be calculated.

Concept introduction:

The pH of a solution is define as a figure that expresses the acidity of the alkalinity of a given solution.

The pH of a solution is calculated by the formula, pH=log[H+]

The sum, pH+pOH=14

The value of Kw is calculated by the formula,

Kw=KaKb

To determine: The pH of the given solution.

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