   Chapter 15, Problem 21QAP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
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# An aqueous solution is to be prepared that will be 7.51% by mass ammonium nitrate. What mass of NH4NO3 and what mass of water will be needed to prepare 1.25 kg of the solution?

Interpretation Introduction

Interpretation:

The masses of NH4NO3 and water needed to prepare 1.25kg of the solution are to be calculated.

Concept Introduction:

Solution is composed of solute and solvent particles. Solute particles are always present in a lower amount as compared to the amount of the solvent in the solution. The solution can be concentrated and diluted on the basis of number of moles of solute present in the particular amount of the solvent. Mass percent is used to describe the quantity of a substance in the solution.

Explanation

The mass of a solution is given to be 1.25kg.

The percentage of NH4NO3 is given to be 7.51%.

The conversion of units of mass of a solution into g is done as,

1.25kg=1.25×1000g=1250g

The percentage of water present in a solution is calculated as shown below.

Percentageofwater=100PercentageofNH4NO3 (1)

Substitute the value of percentage of NH4NO3 in the equation (1).

Percentageofwater=1007.51%=92.49%

The mass of NH4NO3 present in the solution is calculated by the formula,

MassofNH4NO3=Massofsolution×PercentageofNH4NO3100 (2)

Substitute the values of mass of solution and percentage of NH4NO3 in the above expression

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