   # The equilibrium constant K for the reaction CO 2 (g) ⇄ CO(g) + ½ O 2 (g) is 6.66 × 10 −12 at 1000 K. Calculate K for the reaction 2 CO(g) + O 2 (g) ⇄ 2 CO 2 (g) ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 15, Problem 22PS
Textbook Problem
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## The equilibrium constant K for the reactionCO2(g) ⇄ CO(g) + ½ O2(g)is 6.66 × 10−12 at 1000 K. Calculate K for the reaction2 CO(g) + O2(g) ⇄ 2 CO2(g)

Interpretation Introduction

Interpretation: The equilibrium constant of the given reaction is to be calculated.

Concept introduction:

Equilibrium constant: It is the ratio of products to reactants has a constant value when the reaction is in equilibrium at a certain temperature. And it is represented by the letter K.

For a reaction,

aA+bBcC+dD

The equilibrium constant is, K=[C]c[D]d[A]a[B]b, where, a, b, c and d are the stoichiometric coefficients of reactant and product in the reactions.

### Explanation of Solution

The equilibrium constant of the given reaction is calculated.

Given,

Equilibrium constant at 1000K, K1=6.66×1012

The balanced chemical equation for the first reaction is,

CO2(g)CO(g)+12O2(g)

The equilibrium constant for the reaction is,’

K1=[CO][O2]1/2[CO2]=6.66×1012

The balanced chemical equation for the second reaction is

2CO(g)+O2(g)2CO2(g)

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