   # For each of the following pairs of solids, determine which solid has the smallest molar solubility. a. FeC 2 O 4 , K sp = 2.1 × 10 −7 , or Cu(IO 4 ) 2 , K sp = 1.4 × 10 −7 b. Ag 2 CO 3 , K sp = 8.1 × 10 −12 , or Mn(OH) 2 , K sp = 2 × 10 −13 ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 15, Problem 36E
Textbook Problem
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## For each of the following pairs of solids, determine which solid has the smallest molar solubility.a. FeC2O4, Ksp = 2.1 × 10−7, or Cu(IO4)2, Ksp = 1.4 × 10−7b. Ag2CO3, Ksp = 8.1 × 10−12, or Mn(OH)2, Ksp = 2 × 10−13

(a)

Interpretation Introduction

Interpretation: The solubility product of each pair of solids is given. The solid that has the smallest molar solubility is to be identified from each given pairs.

Concept introduction: Solubility is defined as the maximum amount of solute that can dissolve at a certain amount of solvent at certain temperature. The solubility product, Ksp is the equilibrium constant that is applied when salt partially dissolve in a solvent. The solubility product of dissociation of AxBy is calculated as,

Ksp=[A]x[B]y

### Explanation of Solution

Explanation

To identify: The solid that has the smallest molar solubility from FeC2O4 and Cu(IO4)2

The solubility of FeC2O4 is 4.6×104mol/L_ .

Given

Solubility product of FeC2O4 is 2.1×107 .

Since, solid FeC2O4 is placed in contact with water. Therefore, compound present before the reaction is FeC2O4 and H2O . The dissociation reaction of FeC2O4 is,

FeC2O4(s)Fe2+(aq)+C2O42(aq)

Since, FeC2O4 does not dissolved initially, hence,

[Fe2+]initial=[C2O42]initial=0

The solubility of FeC2O4 can be calculated from the concentration of ions at equilibrium.

It is assumed that smol/L of solid is dissolved to reach the equilibrium. The meaning of 1:1 stoichiometry of salt is,

smol/LFeC2O4smol/LFe2++smol/LC2O42

Make the ICE table for the dissociation reaction of FeC2O4 .

FeC2O4(s)Fe2+(aq)C2O42(aq)Initial(M):00Chang(M):ssEquilibrium(M):ss

Formula

The solubility product of FeC2O4 is calculated as,

Ksp=[Fe2+][C2O42]=(s)(s)

Where,

• Ksp is solubility product.
• [Fe2+] is concentration of Fe2+ .
• [C2O42] is concentration of C2O42 .
• s is the solubility.

Substitute the values of Ksp in the above expression.

Ksp=(s)(s)2.1×107=s2s=4.6×104mol/L_

The solubility of Cu(IO4)2 is 3.3×103mol/L_ .

Given

Solubility product of Cu(IO4)2 is 1.4×107

(b)

Interpretation Introduction

Interpretation: The solubility product of each pair of solids is given. The solid that has the smallest molar solubility is to be identified from each given pairs.

Concept introduction: Solubility is defined as the maximum amount of solute that can dissolve at a certain amount of solvent at certain temperature. The solubility product, Ksp is the equilibrium constant that is applied when salt partially dissolve in a solvent. The solubility product of dissociation of AxBy is calculated as,

Ksp=[A]x[B]y

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