   Chapter 15, Problem 38QAP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
20 views

# 38. How many grams of formaldehyde are in 113.1 mL of a 3.0 M aqueous solution of formaldehyde? The formula for formaldehyde is HCHO.

Interpretation Introduction

Interpretation:

The grams of formaldehyde in aqueous solution of formaldehyde are to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

Moles=MassgMolarmass

The molarity is calculated by the formula,

Molarity=NumberofmolesofsoluteVolumeofsolution (L).

Explanation

It is given that 113.1mL of 3.0M aqueous solution of formaldehyde is prepared.

The formula of formaldehyde is given to be HCHO.

The molar mass of HCHO is calculated as shown below.

MolarmassofHCHO=2AtomicmassofH+AtomicmassofC+AtomicfmassofO=21+12+16g/mol=30g/mol

The conversion of units of 113.1mL into L is done as,

113.1mL=113.11000L=0

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