   Chapter 15, Problem 42QAP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
1 views

# 42. Standard silver nitrate solutions are used in the analysis of samples containing chloride ion. How many grams of silver nitrate are needed to prepare 250. mL of a 0.100 M AgNO3 solution?

Interpretation Introduction

Interpretation:

The grams of silver nitrate needed to prepare a given solution are to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

Moles=MassgMolarmass

The molarity is calculated by the formula,

Molarity=NumberofmolesofsoluteLitersofsolution.

Explanation

It is given that 250.0mL of a 0.100M

AgNO3 solution is prepared.

The molar mass of AgNO3 is calculated as shown below.

MolarmassofAgNO3=AtomicmassofAg+AtomicmassofN+3AtomicmassofO=107.9+14+316g/mol=169.9g/mol

The conversion of units of volume into L is done as,

250.0mL=250.01000L=0

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