Chapter 15, Problem 4PE

### College Physics

1st Edition
Paul Peter Urone + 1 other
ISBN: 9781938168000

Chapter
Section

### College Physics

1st Edition
Paul Peter Urone + 1 other
ISBN: 9781938168000
Textbook Problem

# What is the change in internal energy of a system which does 4.50 × 10 5 J of work while 3.00 × 10 6 J of heat transfer occurs into the system, and 8.00 × 10 6 J of heat transfer occurs to the environment?

To determine

The change in internal energy of the system.

Explanation

Given info:

Heat transfer into the system, Qin=3.00Ã—106Â J.

Heat transfer from the system to the environment, Qout=âˆ’8.00Ã—106Â J.

Net heat transfer =Î”Q=?

Work is done by the system W=4.50Ã—105Â J (positive since work is being done by the system)

Change in internal energy =Î”U=?

Formula Used:

Net Heat transfer is given as

Î”Q=Qin+Qout

According to the first law of thermodynamics, we have

Î”Q=Î”U+W

Calculation:

Net heat transfer is given as,

Î”Q=Qin+Qout

Inserting the values

Î”Q=3

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