   Chapter 15, Problem 55AP

Chapter
Section
Textbook Problem

In deep spare, two spheres each of radius 5.00 m are connected by a 3.00 × 102 m nonconducting cord. If a uniformly distributed charge of 35.0 mC resides on the surface of each sphere, calculate the tension in the cord.

To determine
The tension in the cord.

Explanation

Given info: The radius (R) of the spheres is 5.00 m. The length of the cord (l) is 3.00×102m . The charge on the spheres (Q) is 35.0 mC.

The tension in the cord is equal to the electrostatic force of repulsion between the sphres.

Formula to calculate the tension is,

T=keQ2r2

• ke is the Coulomb constant.
• r is the distance of separation between the spheres.

The distance of separation is,

r=l+2R

Therefore,

T=keQ2(l+2R)2

Substitute 8.99×109 Nm2/C2 for ke , 5.00 m for R, 3.00×102m for l and 35.0 mC for Q.

T=(8

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