   Chapter 15, Problem 58QAP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
63 views

# 58. For convenience, one form of sodium hydroxide that is sold commercially is the saturated solution. This solution is 19.4 M, which is approximately 50’k by mass sodium hydroxide. What volume of this solution would be needed to prepare 3.50 L of 3.00 M NaOH solution?

Interpretation Introduction

Interpretation:

The volume of the solution that would be needed to prepare 3.50L of 3.00M

NaOH solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The moles of any element is calculated by the formula,

Moles=MassgMolarmass

Molarity is used to find out the concentration of solution.

The molarity is calculated by the formula,

Molarity=NumberofmolesofsoluteVolumeofsolutionL.

Explanation

The value of M1, M2 and V2 of the NaOH solution is given to be 19.4M, 3.00M and 3.50L respectively.

The relationship between molarity and volume is shown below.

M1V1=M2V2

Where,

• M1 is the initial molarity of the solution.
• V1 is the initial volume of the solution.
• M2 is the final molarity of the solution.
• V2 is the final volume of the solution.

Rearrange an above expression to calculate the volume needed to prepare the solution

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started 