   Chapter 15, Problem 59AP

Chapter
Section
Textbook Problem

A proton moving at v0 = 1.50 × 106 m/s enters the region between two parallel plates with charge densities of magnitude σ = 4.20 × 10−9 C/m2 (Fig. P15.59). Calculate (a) the magnitude of the electric field between the plates, and (b) the magnitude of the electric force acting on the proton. (c) Find the y-displacement of the proton when it reaches the far edge of the plates, a horizontal distance d = 2.00 × 10−2 m from where it entered. Assume that the proton does not hit cither of the plates, and that upward is the positive y-direction. Figure P15.59

(a)

To determine
The electric field between the plates.

Explanation

Given info: The surface charge density is σ=4.20×109C/m2 .

Formula to calculate the electric field is,

E=σε0

• ε0 is the permittivity of free space.

Substitute 8.85×1012 C2/Nm2 for ε0 , 4

(b)

To determine
The electric force on the proton.

(c)

To determine
The y displacement of the proton.

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