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Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

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BuyFindarrow_forward

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

At 1800 K, oxygen dissociates very slightly into its atoms.

O2(g) ⇄ 2 O(g)    KP= 1.2 × 10−10

If you place 0.050 mol of O2 in a 10.-L vessel and heat it to 1800 K, how many O atoms are present in the flask?

Interpretation Introduction

Interpretation:

The number of oxygen atoms present in the flask in the dissociation of oxygen molecule into its atoms has to be calculated.

Concept Introduction:

Equilibrium constant in terms of pressure[Kp]: Equilibrium constant can be expressed in terms of partial pressures in atmospheres.

aA(g)+bB(g)cC(g)+dD(g)KP=PCc×PDdPAa×PBb

The activity of solid substance will not appear in equilibrium and numerically it is considered as one.

Kp=Kc(RT)ΔnKc-EquilibriumconstantintermsofconcentrationKp-EquilibriumconstantintermsofpressureΔn-changeinnumberofmoles

Explanation

Given:

O2(g)2O(g)Kp=1.2×10-10V=10LT=1800KnO2=0.050

Using the equation Kp=Kc(RT)Δn we can find out the value of Kc

Kp=Kc(RT)ΔnKc=Kp(RT)Δn=1.2×10-10(0.082×1800)2-1=8.12×10-13

O2(g)2O(g)Initialconcentration0

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