Physics for Scientists and Engineers: Foundations and Connections
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN: 9781133939146
Author: Katz, Debora M.
Publisher: Cengage Learning
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Chapter 15, Problem 78PQ

Case Study Shannon uses the example of a helium balloon to explain the buoyant force. Large helium “blimp” balloons are sometimes used as an advertisement (Fig. P15.78). The blimp balloon has a volume of 42.8 m3, and the mass of the empty blimp is 13.6 kg. It is held down by either a large-link steel chain or a large-link aluminum chain. Each link of steel has a mass of 2.6 kg, and each link of aluminum has a mass of 0.87 kg. The chain rests on the ground but is not attached to it. The density of helium gas is 0.180 kg/m3. a. How many links hang from the blimp if the steel chain is used? b. Compare your answer with the number of links that would hang if the aluminum chain were used instead.

Chapter 15, Problem 78PQ, Case Study Shannon uses the example of a helium balloon to explain the buoyant force. Large helium

FIGURE P15.78

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Chapter 15 Solutions

Physics for Scientists and Engineers: Foundations and Connections

Ch. 15 - Crater Lake in Oregon is the deepest lake in the...Ch. 15 - Prob. 6PQCh. 15 - Prob. 7PQCh. 15 - One study found that the dives of emperor penguins...Ch. 15 - Prob. 9PQCh. 15 - Prob. 10PQCh. 15 - Suppose you are at the top of Mount Everest and...Ch. 15 - Prob. 12PQCh. 15 - Prob. 13PQCh. 15 - Prob. 14PQCh. 15 - A 20.0-kg child sits on a four-legged stool. The...Ch. 15 - Prob. 16PQCh. 15 - The dolphin tank at an amusement park is...Ch. 15 - Prob. 18PQCh. 15 - A block of an unknown material floats in water...Ch. 15 - Prob. 20PQCh. 15 - Prob. 21PQCh. 15 - A spherical submersible 2.00 m in radius, armed...Ch. 15 - What fraction of an iceberg floating in the ocean...Ch. 15 - Prob. 24PQCh. 15 - A hollow copper (Cu = 8.92 103 kg/m3) spherical...Ch. 15 - Prob. 26PQCh. 15 - You have probably noticed that carrying a person...Ch. 15 - A straw is in a glass of juice. Peter puts his...Ch. 15 - Prob. 29PQCh. 15 - Prob. 30PQCh. 15 - Prob. 31PQCh. 15 - Prob. 32PQCh. 15 - A rectangular block of Styrofoam 25.0 cm in...Ch. 15 - Prob. 34PQCh. 15 - Prob. 35PQCh. 15 - A manometer is shown in Figure P15.36. Rank the...Ch. 15 - The gauge pressure measured on a cars tire is 35...Ch. 15 - Prob. 38PQCh. 15 - Prob. 39PQCh. 15 - To allow a car to slow down or stop, hydraulic...Ch. 15 - Prob. 41PQCh. 15 - Prob. 42PQCh. 15 - Prob. 43PQCh. 15 - Water enters a smooth, horizontal tube with a...Ch. 15 - Prob. 45PQCh. 15 - Prob. 46PQCh. 15 - Prob. 47PQCh. 15 - A fluid flows through a horizontal pipe that...Ch. 15 - Water is flowing through a pipe that has a...Ch. 15 - Prob. 50PQCh. 15 - Prob. 51PQCh. 15 - Figure P15.52 shows a Venturi meter, which may be...Ch. 15 - At a fraternity party, drinking straws have been...Ch. 15 - Liquid toxic waste with a density of 1752 kg/m3 is...Ch. 15 - Water is flowing in the pipe shown in Figure...Ch. 15 - Prob. 56PQCh. 15 - Water flows through a pipe that gradually descends...Ch. 15 - Air flows horizontally with a speed of 108 km/h...Ch. 15 - Prob. 59PQCh. 15 - Prob. 60PQCh. 15 - Prob. 61PQCh. 15 - Prob. 62PQCh. 15 - Prob. 63PQCh. 15 - Prob. 64PQCh. 15 - Prob. 65PQCh. 15 - Prob. 66PQCh. 15 - Prob. 67PQCh. 15 - Prob. 68PQCh. 15 - Prob. 69PQCh. 15 - Prob. 70PQCh. 15 - The density of air in the Earths atmosphere...Ch. 15 - A manometer containing water with one end...Ch. 15 - Prob. 73PQCh. 15 - Prob. 74PQCh. 15 - Prob. 75PQCh. 15 - Prob. 76PQCh. 15 - Prob. 77PQCh. 15 - Case Study Shannon uses the example of a helium...Ch. 15 - Prob. 79PQCh. 15 - Prob. 80PQCh. 15 - A uniform wooden board of length L and mass M is...
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  • A fluid flows through a horizontal pipe that widens, making a 45 angle with the y axis (Fig. P15.48). The thin part of the pipe has radius R, and the fluids speed in the thin part of the pipe is v0. The origin of the coordinate system is at the point where the pipe begins to widen. The pipes cross section is circular. a. Find an expression for the speed v(x) of the fluid as a function of position for x 0 b. Plot your result: v(x) versus x. FIGURE P15.48 (a) The continuity equation (Eq. 15.21) relates the cross-sectional area to the speed of the fluid traveling through the pipe. A0v0 = A(x)v(x) v(x)=A0v0A(x) The cross sectional area is the area of a circle whose radius is y(x). The widening pan of the pipe is a straight line with slope of 1 and intercept y(0) = R. y(x) = mx + b = x + R A(x) = [y(x)]2 = (x + R)2 Plug this into the formula for the velocity. Plug this into the formula for the velocity. v(x)=A0v0(x+R)2
    A 10.0-kg block of metal measuring 12.0 cm by 10.0 cm by 10.0 cm is suspended from a scale and immersed in water as shown in Figure P15.24b. The 12.0-cm dimension is vertical, and the top of the block is 5.00 cm below the surface of the water. (a) What are the magnitudes of the forces acting on the top and on the bottom of the block due to the surrounding water? (b) What is the reading of the spring scale? (c) Show that the buoyant force equals the difference between the forces at the top and bottom of the block.
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  • What is the pressure inside an alveolus having a radius of 2.50104 m if the surface tension of the fluid-lined wall is the same as for soapy water? You may assume the pressure is the same as that created by a spherical bubble.
    Figure P15.52 shows a Venturi meter, which may be used to measure the speed of a fluid. It consists of a Venturi tube through which the fluid moves and a manometer used to measure the pressure difference between regions 1 and 2. The fluid of density tube moves from left to right in the Venturi tube. Its speed in region 1 is v1, and its speed in region 2 is v2. The necks cross-sectional area is A2, and the cross-sectional area of the rest of the tube is A1. The manometer contains a fluid of density mano. a. Do you expect the fluid to be higher on the left side or the right side of the manometer? b. The speed v2 of the fluid in the neck comes from measuring the difference between the heights (yR yL) of the fluid on the two sides of manometer. Derive an expression for v2 in terms of (yR yL), A1, A2, tube, and mano. FIGURE P15.52
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