   Chapter 15, Problem 7PS

Chapter
Section
Textbook Problem

The reactionPCl5(g) ⇄ PCl3(g) + Cl2(g)was examined at 250 °C. At equilibrium, [PCl5] = 4.2 × 10‒5 mol/L, [PCl3] = 1.3 × 10‒2 mol/L, and [Cl2] = 3.9 × 10−3 mol/L. Calculate Kc, for the reaction.

Interpretation Introduction

Interpretation: Interpretation:

The equilibrium constant for the given reaction has to be identified.

Concept Introduction:

At equilibrium the concentration of the reaction and the product is equated to a constant K, where K is known as the equilibrium

If a reaction is as aA+bBcC+dD ,

The equilibrium constant K=[C]c[D]d[A]a[B]b

Explanation

From the table given below,

 Equation PCl5 PCl3 Cl2 Equilibrium 4.2 × 10−5 1.3 × 10−2 3.9 × 10−3

Kc can be calculated as

K<

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