# The number of real solutions with the help of discriminant.

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

#### Solutions

Chapter 1.5, Problem 82E
To determine

## The number of real solutions with the help of discriminant.

Expert Solution

There will be two real roots for the equation.

### Explanation of Solution

Given information:

x2+2.21x+1.21=0

Formula used: -

When  b24ac=0  there is one real root.

When  b24ac>0  there are two real roots.

When  b24ac<0  there are two complex roots.

x2+2.21x+1.21=0

Now, finding discriminant to find number of real solutions:

a=1,b=2.21,c=1.21

b24ac=(2.21)24(1)(1.21)b24ac=4.884.84b24ac=0.04b24ac>0

Hence, there will be two real roots for equation x2+2.21x+1.21=0 .

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