   Chapter 15, Problem 83QAP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
30 views

# 83. A solution of phosphoric acid, H3PO4, is found to contain 35.2 g of H3PO4 per liter of solution. Calculate the molarity and normality of the solution.

Interpretation Introduction

Interpretation:

The molarity and normality of the given solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

Moles=MassgMolarmass

The molarity is calculated by the formula,

Molarity=NumberofmolesofsoluteVolumeofsolutionL

The normality of the solution is calculated by the formula,

Normality=Molarity×NumberofH+orOHions.

Explanation

The mass and volume of H3PO4 solution is given to be 35.2g and 1L.

The molar mass of H3PO4 is 98g/mol.

The number of moles of H3PO4 in a solution is calculated by the formula,

Moles=MassgMolarmass        (1)

Substitute the values of mass and molar mass in the equation (1).

Moles=35.2g98g/mol=0.359moles

The molarity is calculated by the formula,

Molarity=NumberofmolesofsoluteVolumeofsolutionL        (2)

Substitute the values of number of moles of solute and volume of the solution in the equation (2)

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