   Chapter 15, Problem 87QAP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
3 views

# 87. What volume of 0.151 N NaOH is required to neutralize 24.2 mL of 0.125 N H2SO4? What volume of 0.151 N NaOH is required to neutralize 24.2 n1L of 0.125 M H2SO4?

Interpretation Introduction

Interpretation:

The volume of 0.151NNaOH required to neutralize 24.2mL of 0.125NH2SO4 and 24.2mL of 0.125MH2SO4 is to be calculated.

Concept Introduction:

Neutralization is the process in which an acid and base react with each other to give salt and water. The general reaction of acid and base is represented as:

AH+BOHAB+H2O

The normality of a solution is defined as the gram equivalent weight of a solute dissolved in one liter of the solution.

Molarity of a solution is defined as the number of moles of solute dissolved in one liter of the solution.

Explanation

The normality of the given NaOH solution is 0.151N.

The normality of the H2SO4 solution is 0.125N.

The volume of 0.125NH2SO4 solution is 24.2mL.

The relation between the volume of acid and base required for neutralization is represented as:

NaVa=NbVb        (1)

Where,

• Na represents the normality of the acid.
• Nb represents the normality of the base.
• Va represents the volume of acid.
• Vb represents the volume of base.

Rearrange the equation (1) to obtain the value of Vb.

Vb=NaVaNb        (2)

Substitute the value of Na, Nb and Va in the equation (1).

Vb=0.125N24.2mL0.151N=20.03mL

The volume of 0.151NNaOH required to neutralize 24.2mL of 0.125NH2SO4 is 20.03mL.

The molarity of the second solution of H2SO4 is 0.125M.

The volume of 0.125MH2SO4 solution is 24

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