# Find the real solutions of equation.

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

### Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

#### Solutions

Chapter 1.5, Problem 88E
To determine

## Find the real solutions of equation.

Expert Solution

No real solution exists.

### Explanation of Solution

Given information:

1x12x2=0

Formula used: -

First, we will solve this equation by cross multiplication method and then we will find value of x.

x=b±b24ac2a

1x12x2=0

Now by applying cross multiplication method:

1x12x2=0x22(x1)x2(x1)=0x22x+2=0

x=b±b24ac2a In equation x22x+2=0

Here a=1,b=2,c=2

x=(2)±(2)24(1)(2)2(1)x=2±482x=2±42

Because, b24ac=4<0

Therefore, no real solution exists.

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