   # The Hg 2+ ion forms complex ions with I − as follows: Hg 2+ ( a q ) + I − ( a q ) ⇌ H g I + ( a q ) K 1 = 1.0 × 10 8 HgI + ( a q ) + I − ( a q ) ⇌ H g I 2 ( a q ) K 2 = 1.0 × 10 5 HgI 2 ( a q ) + I − ( a q ) ⇌ H g I 3 − ( a q ) K 3 = 1.0 × 10 9 HgI 3 − ( a q ) + I − ( a q ) ⇌ H g I 4 2 − ( a q ) K 4 = 1.0 × 10 8 A solution is prepared by dissolving 0.088 mole of Hg(NO 3 ) 2 and 5.00 moles of NaI in enough water to make 1.0 L of solution. a. Calculate the equilibrium concentration of [HgI 4 2− ]. b. Calculate the equilibrium concentration of [I − ]. c. Calculate the equilibrium concentration of [Hg 2+ ]. ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 15, Problem 98CWP
Textbook Problem
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## The Hg2+ ion forms complex ions with I− as follows: Hg 2+ ( a q )   +   I − ( a q )   ⇌   H g I + ( a q )   K 1   =   1.0   ×   10 8 HgI + ( a q )   +   I − ( a q )   ⇌   H g I 2 ( a q )   K 2   =   1.0   ×   10 5 HgI 2 ( a q )   +   I − ( a q )   ⇌   H g I 3 − ( a q )   K 3   =   1.0   ×   10 9 HgI 3 − ( a q )   +   I − ( a q )   ⇌   H g I 4 2 − ( a q )   K 4   =   1.0   ×   10 8 A solution is prepared by dissolving 0.088 mole of Hg(NO3)2 and 5.00 moles of NaI in enough water to make 1.0 L of solution.a. Calculate the equilibrium concentration of [HgI42−].b. Calculate the equilibrium concentration of [I−].c. Calculate the equilibrium concentration of [Hg2+].

(a)

Interpretation Introduction

Interpretation: The equilibrium concentration of [HgI42] has to be calculated.

Concept introduction: Equilibrium concentration is defined as the state when reactants and products are present in concentrations which do not change with time. The equilibrium concentration occurs when the rate of forward reaction becomes equal to the rate of backward reaction.

### Explanation of Solution

Explanation

To determine: The equilibrium concentration of [HgI42] .

Given

The moles of Hg(NO3)2 is 0.088 mole .

The moles of NaI is 5.00 mole .

The volume of Answer is 1.0 L .

The given reactions are,

Hg2+(aq)+I(aq)HgI+(aq)     K1=1.0×108 (1)

HgI+(aq)+I(aq)HgI2(aq)     K2=1.0×105 (2)

HgI2(aq)+I(aq)HgI3(aq)     K3=1.0×109 (3)

HgI3(aq)+I(aq)HgI42(aq)     K4=1

(b)

Interpretation Introduction

Interpretation: The equilibrium concentration of [I] has to be calculated.

Concept introduction: Equilibrium concentration is defined as the state when reactants and products are present in concentrations which do not change with time. The equilibrium concentration occurs when the rate of forward reaction becomes equal to the rate of backward reaction.

(c)

Interpretation Introduction

Interpretation: The equilibrium concentration of [Hg2+] has to be calculated.

Concept introduction: Equilibrium concentration is defined as the state when reactants and products are present in concentrations which do not change with time. The equilibrium concentration occurs when the rate of forward reaction becomes equal to the rate of backward reaction.

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