BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071
BuyFind

Precalculus: Mathematics for Calcu...

6th Edition
Stewart + 5 others
Publisher: Cengage Learning
ISBN: 9780840068071

Solutions

Chapter 1.5, Problem 98E
To determine

Find the real solutions of equation.

Expert Solution

Answer to Problem 98E

  x=33,x=1

Explanation of Solution

Given information:

  x62x33=0

Formula used: -

  x=b±b24ac2a

  x62x33=0

Assuming x3=z in above equation, new equation will be:

  z22z3=0

Now using x=b±b24ac2a in the equation z22z3=0

  a=1,b=2,c=3

  z=(2)±(2)24(1)(3)2(1)z=2±4+122z=2±162z=2±42

  z=242,z=2+42z=3,z=1

Now substituting value of z=x3 in place of z

  x3=3,x3=1x=33,x=1

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