   Chapter 15.1, Problem 9E

Chapter
Section
Textbook Problem

Evaluate the double integral by first identifying it as the volume of a solid.9. ∬ R 2 d A ,   R = { ( x , y ) | 2 ≤ x ≤ 6 , − 1 ≤ y ≤ 5 }

To determine

To evaluate: The value of given double integral over the rectangular region R.

Explanation

Given:

The function is, f(x,y)=2 .

The rectangular region, R={(x,y)|2x6,1y5} .

Interpretation:

From the given f(x,y) and R, it is observed that the surface is a rectangular solid.

Calculation:

Since f(x,y)=2 is greater than 0, it is enough to evaluate the value of double integral in order to find the volume of the solid.

R2dA=26[152dy]dx=

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