   Chapter 15.4, Problem 15.3SC ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
1 views

# ercise 15.3 Calculate the molarity of a solution prepared by dissolving I .00 g of ethanol. C2HOH. in enough water to give a final volume of 101 mL.

Interpretation Introduction

Interpretation:

The molarity of the solution which is prepared by 1.00 g of ethanol in enough water to give a final volume of 101 mL should be calculated.

Concept Introduction:

Molarity of the solution is equal to the ratio of number of moles of solute to the volume of solution in litres.

The mathematical expression is given by:

Molarity = number of moles of solute volume of solution in litres

Number of moles = given massmolar mass.

Explanation

Given information:

Volume of solution = 101 mL

Mass of ethanol (solute) = 1.00 g

First, calculate the number of moles of ethanol:

Number of moles = given massmolar mass

Molar mass of ethanol = 46.07 g/mol

Put the values,

Number of moles = 1.00 g46.07 g/mol=0.02170 mol

Number of moles of ethanol = 2.17×102 mol

The mathematical expression for molarity:

Molarity = number of moles of solute

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started 